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GREYUIT [131]
3 years ago
10

The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the

equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.
Chemistry
1 answer:
kow [346]3 years ago
7 0
Br_{2} + Cl_{2}---\ \textgreater \   2BrCl

K_{eq} = \frac{[BrCl]^{2}}{[Br_{2}][Cl_{2}]]} = \frac{[1.5*10^{-2}]^{2}}{[2.2*10^{-3}][3.0*10^{-2}]} =0.34*10=3.4

K_{eq}=3.4
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