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GREYUIT [131]
3 years ago
10

The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the

equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.
Chemistry
1 answer:
kow [346]3 years ago
7 0
Br_{2} + Cl_{2}---\ \textgreater \   2BrCl

K_{eq} = \frac{[BrCl]^{2}}{[Br_{2}][Cl_{2}]]} = \frac{[1.5*10^{-2}]^{2}}{[2.2*10^{-3}][3.0*10^{-2}]} =0.34*10=3.4

K_{eq}=3.4
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A certain first-order reaction has a rate constant of 2.75 10-2 s−1 at 20.°c. what is the value of k at 45°c if ea = 75.5 kj/mol
Gekata [30.6K]

Answer:

0.314 s⁻¹  

Step-by-step explanation:

Use the <em>Arrhenius equation.</em>

\ln( \frac{k_2 }{k_1 }) = (\frac{E_{a} }{R })(\frac{ 1}{T_1} - \frac{1 }{T_2 })\\

Data:

k₁ = 0.0275 s⁻¹;            k₂ = ?

Eₐ = 75.5 kJ·mol⁻¹

T₁ = 20 °C = 293.15 K; T₂ = 45°C = 318.15 K

<em>Calculation: </em>

\ln(\frac{k_{2} }{0.0275}) = (\frac{75 500 }{8.314})(\frac{ 1}{293.15} - \frac{1 }{318.15 })

\ln(\frac{k_{2} }{0.0275}) = 9081\times 2.681 \times10^{-4}

\ln(\frac{k_{2} }{0.0275}) = 2.434

\frac{k_{2} }{0.0275} = \text{e}^{2.434}

\frac{k_{2} }{0.0275} = 11.41

k₂ = 0.0275 × 11.41

k₂ = 0.314 s⁻¹

3 0
3 years ago
Chemical weathering change the ___ of rock​
a_sh-v [17]

Answer:

Chemical weathering is the process by which rocks are broken down by chemical reaction.

Explanation:

Chemical weathering is the weakening and subsequent disintegration of rock by chemical reactions. These reactions include oxidation, hydrolysis, and carbonation. These processes either form or destroy minerals, thus altering the nature of the rock's mineral composition.

5 0
3 years ago
How many molecules are in 2.50 moles of SO2
dusya [7]

Every compound or element has a fixed number of molecules per mole. This is given by the Avogadros number which is about 6.022 x 10^23 molecules per mole. Therefore:

 

molecules = 2.50 moles * (6.022 x 10^23 molecules / mole)

<span>molecules = 1.5055 x 10^24 molecules of SO2</span>

7 0
3 years ago
10. A sample of an unknown composition was tested in a laboratory. The sample could not be broken down by
damaskus [11]

Answer:

it would be an element because its an element

Explanation:

8 0
3 years ago
Read 2 more answers
PLS ANSWER FAST WILL GIVE BRAINLY!!!!
castortr0y [4]
False because the sugar is just changing it’s form
7 0
3 years ago
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