-12.25 in simlplest form is -12/25 it cannot be simplified anymore
Answer:
your equation should look like:
y+6= -3(x-4)
Answer:
15.3feet
Step-by-step explanation:
Given the scale model of a train as;
2cm = 3feet
We are to find the height of real train of height 10.2cm, we can write;
10.2cm = x
Divide both expressions
2/10.2 = 3/x
2x = 3×10.2
2x = 30.6
x= 15.3
Hence the height if the real train is 15.3feet
Answer:
6F
Step-by-step explanation:
Let x be the temperature at noon
dropping means we subtract
The temperature at 9 pm was -4. That goes on the right hand side of the equals
x-10 = -4
Add 10 to each side
x-10+10 = -4+10
x = 6
The temperature at noon was 6 F
Step 1: Group this into two groups:

When you do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.
Step 2: Factor out the GCF from both individual groups:

Step 3: Notice both groups have that (h+2)? That's a new GCF between the two groups, so factor that out:

Step 4: That
piece can be factored further, since it's a difference of squares:

Now it's factored.