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seropon [69]
2 years ago
7

Please answer these I’m desperate. It’s do tomorrow and I only have those left so please. Btw they are two separate questions. I

already answered have of it I just need to find the final answer.
Instructions: preform the operations to climb the pyramid multiply to move up the pyramid and divide to move down the pyramid.

Mathematics
1 answer:
luda_lava [24]2 years ago
5 0

Answer:

it's 3

Step-by-step explanation:

I did this stuff in 6th grade it was really easy

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Kobe reported that the local waterslides have 30 employees of which 90 percent are temporary. How many temporary employees are t
Dmitriy789 [7]

Answer:

27 temporary employees

Step-by-step explanation:

Given information: 30 employees, 90% temporary

To find the number of temporary employees we can do:  30*90%=30*0.9=27

There are 27 temporary employees

7 0
2 years ago
CD and CB are tangent to circle A. If CD = 5x – 13 and CB = 12, find x.<br>​
hoa [83]

Answer:

5

Step-by-step explanation:

because 5•5=25 and 25-13=12

6 0
3 years ago
a basket contains 3 apples, 4 oranges, and 5 mangos. Without looking you select a fruit at random, replace it, and select a diff
FinnZ [79.3K]

Answer:

5/48

Step-by-step explanation:

probabilty= 5/12 * 3/12

8 0
3 years ago
Hello fellow people please asnwer this will give brainliest if right!
elena-14-01-66 [18.8K]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
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