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Cerrena [4.2K]
3 years ago
6

The following question has two parts. First, answer part A. Then, answer part B.

Mathematics
2 answers:
dsp733 years ago
7 0

Answer: part a is 11

Step-by-step explanation:

Elan Coil [88]3 years ago
5 0
Part A is 11 I think
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What are the partial products of 35x7
Ludmilka [50]
35*7
= (30+5)*7
= 210+ 35
= 245

The final answer is 245~
6 0
3 years ago
The estimate regression equation for a model involving two independent variables and 10 observations follows.
True [87]

Answer:

a) b_1 = 0.5906\\b_2 = 0.4980

b) y = 289.815

Step-by-step explanation:

We are given the following information:

The estimate regression equation for a model involving two independent variables and 10 observations follows:

y = 29.1270 + 0.5906x_1 + 0.4980x_2

where x_1, x_2 are the two independent variable and y is the dependent variable.

a) The regression line is of the form:

y = b_0 + b_1x_1 + b_2x_2\\\text{where } b_0 \text{ is the y-intercept and }b_1, b_2\text{ are the coefficients of} x_1, x_2\text{ respectively}

Comparing, we get,

b_1 = 0.5906\\b_2 = 0.4980

These are the coefficients of x_1, x_2 respectively, and helps us to know the the significance of the independent variable in predicting the independent variable.

b) We have to estimate y when

x_1 = 180 \text{ and } x_2 = 310\\y = 29.1270 + 0.5906x_1 + 0.4980x_2\\\text{Putting values}\\y = 29.1270 + 0.5906(180) + 0.4980(320)\\y = 289.815

6 0
4 years ago
Part I Instructions: You just started a job at John F. Kennedy Airport. You were hired as a customer service representative and
Verizon [17]
Wouldn't it be B every 10 minutes.
4 0
3 years ago
Which equation represents a circle centered at (3,5) and passing though the point (-2,9)
Maru [420]

The equation represents a circle centered at (3,5) and passing through the point (-2,9) will be,\rm x^2+y^2 -6x-10y-7=0

What exactly is a circle?

It is a point locus drawn equidistant from the center. The radius of the circle is the distance from the center to the circumference.

Given data;

The Centre of the circle is,(h,k)=(3,5)

The circle traverses (-2,9). Consequently, the radius of the circle r is equal to the separation between (3, 4) and (-2,1).

So radius;

r = \sqrt{{{(x_2-x_1)^2 + (y_2-y_1)^2}}

r = \sqrt{{(9-5)^2+(3+2)^2 }

r=\sqrt {41} \\\\ r =6.1 \ units

Now equation of the circle with center (h,k) and radius r is

\rm (x-h)^2 + (y-k)^2 = r^2\\\\ (x-3)^2 + (y-5)^2 = (\sqrt{41})^2\\\\ x^2 - 6x + 9 + y^2 - 10y + 25 = 41

x^2+y^2 -6x-10y-7=0

Hence equation represents a circle that will be,x^2+y^2 -6x-10y-7=0

To learn more about the circle, refer to the link: brainly.com/question/11833983.

#SPJ1

7 0
2 years ago
Can someone help me with questions 22-24? please and thank you
Kryger [21]
(22) 9 less than the quotient of z and 8 (23) 15 minus the quotient of 1.5 and d (24) 2 times the difference of 5 and n
8 0
4 years ago
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