F(x) = (x^2) + x + C at (1,1)
1 = 1 + 1 + C
-1 = C
so,
F(x) = (x^2) + x - 1
Answer:
No
Step-by-step explanation:
If the line did pass through that point, then plugging in the point to the equation would be true. But when you plug in 4 for x, the y would be 18, not 15.
It would cost $50.
20 / 2 = 10
10 x 5 = 50
b = 1/6
Explanation:
3x-y=4 ...1st equation
Rewriting in slope- intercept form:
y = 3x - 4
2y+4bx=1
Rewriting in slope- intercept form:
2y = -4bx + 1
y = -4bx/2 + 1/2
Equation of line: y = mx + c
where m = slope, c = intercept
For a line to be perpendicular to another, the slope of one will be the negative reciprocal of the slope of another.
Slope of the 1st equation = 3
m = 3
reciprocal of 3 = 1/3
negative reciprocal of 3 = -1/3
Slope of the 2nd equation = -4b/2
we equate both slope:
negative reciprocal of 3 = -4b/2
-1/3 = -4b/2
cross multiply:
-1(2) = 3(-4b)
-2 = -12b
Divide both sides by -12:
-2/-12 = -12b/-12
b = 1/6
Hence, the value of b that makes the lines perpendicular is 1/6
