Answer:
The charge for admission is $6 and the charge for each ride is $2
Step-by-step explanation:
Let
x ----> the charge for admission
y ----> the charge for each ride
we have that
-----> equation A
-----> equation B
Solve the system by elimination
Subtract equation B from equation A
Find the value of x
substitute the value of y in any equation
therefore
The charge for admission is $6 and the charge for each ride is $2
4x - 1 < 11
Add 1 to both sides
4x < 12
Divide both sides by 4
x < 3
x is less than 3
Answer:
x^3+6x^2+11x+12
Step-by-step explanation:
(x+4)(x^2+2x+3)
=x(x^2+2x+3)+4(x^2+2x+3) [by multiplying with bith sides]
=x^3+2x^2+3x+4x^2+8x+12
=x^3+2x^2+4x^2+3x+8x+12
=x^3+6x^2+11x+12
(please mark me brainliest)
Cylinder Volume = PI * radius ^2 * height
52 = PI * radius ^2 * 4
radius ^2 = 52 / (PI * 4)
radius ^2 = 52 / 12.5663706144
radius ^ 2 = 4.1380285204
radius = 2.0342144726
OR a good approximation of the radius is 2 inches
