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Ostrovityanka [42]

2 years ago

8

A lawn is in the shape of a trapezoid with a height of 50 feet and bases of 40 feet and 160 feet. How many full bags of fertiliz

er must be purchased to cover the lawn if each full bag covers 5000 square feet and only full bags of fertilizer can be bought?

1 answer:

Alex787 [66]2 years ago

4 0

Answer:

Step-by-step explanation:

Area = 50 × (40+160)/2 =5000 ft^2

You need one bag.

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(36 - 4t) squared.

Flura [38]

Answer: 4(3-t)(3+t)

Step-by-step explanation:

after you find the GCF you will have 4(9-t) squared. since 9 is square you will after to put the square root of 9 (which is 3) into the equation when you factor it further. therefore giving you 4(3-t)(3+t). if you un- factored your equation you would get 4(81-t) because 9x9 is 81 not 3. hope this helps. just learned this too lol

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2 years ago

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jeyben [28]

Answer:

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Step-by-step explanation:

3 0

2 years ago

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

2 years ago

What is 5 3/4 hours after 11:32pm

ASHA 777 [7]

5:17 Am

11:32 + 5 is 4. 32 min plus 45 is 77-60 (which is an hour) is 17 minutes.

4 0

3 years ago

According to the line plot, what is the total distance run for all of the runners combined?

Ostrovityanka [42]

Answer:

Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles

Step-by-step explanation:

1/5 + 2(1/4) + 4(1/3) + 3(1/2)

3 0

2 years ago