Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]
<h3>Factorizing expressions</h3>
Factorization is a way of separating the equations into two separate factors.
Given the expression below;
14xy – 28x – 36y + 48
Group
(14xy – 28x) – (36y + 48)
14x(y - 2) - 12(3y-4)
Factor out the value of 2 from both terms
2[7x(y-2)-6(3y-4)]
Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]
Learn more on factorization here: brainly.com/question/25829061
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Answer:
incomplete
Step-by-step explanation:
please send the full information, I can't see students belonging to acers
Answer:
x = 20
y = 10
m∡8 = 110°
Step-by-step explanation:
m∡1 + m∡2 = 180
5x + y + 3x + y = 180
8x + 2y = 180
m∡1 = m∡8 (they are alternate-exterior angles and are congruent)
5x + y = 3x + 5y
2x = 4y
x = 2y
Substitute '2y' for 'x' in 8x + 2y = 180
8(2y) + 2y = 180
18y = 180
y = 10
x = 2(10)
x = 20
m∡8 = 3(20) + 5(10) = 110°
Answer: the answer should be D
Step-by-step explanation:
