Answer:
Empirical formula is C₅H₁₂O
Molecular formula = C₅H₁₂O
Explanation:
Given data:
Percentage of hydrogen =13.75%
Percentage of carbon = 68.11%
Percentage of oxygen = 18.15%
Empirical formula = ?
Solution:
Number of gram atoms of H = 13.75 / 1.01 = 13.6
Number of gram atoms of O = 18.15 / 16 = 1.13
Number of gram atoms of C = 68.11 / 12 = 5.68
Atomic ratio:
C : H : O
5.68/1.13 : 13.6/1.13 : 1.13/1.13
5 : 12 : 1
C : H : O = 5 : 12 : 1
Empirical formula is C₅H₁₂O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass
:
5×12 + 12×1.01 + 16×1 = 88.12 g/mol
n = 88.17/ 88.12
n = 1
Molecular formula = n (empirical formula)
Molecular formula = 1 (C₅H₁₂O)
Molecular formula = C₅H₁₂O
