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aliina [53]
4 years ago
12

Ionic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in t

he process of forming an ionic bond. Nonmetals, such as chlorine, tend to gain valence electrons in the formation of ionic bonds.
Determine which element(s) are likely to have their electrons stripped away in the formation of ionic bonds. I) aluminum II) sulfur III) oxygen IV) silver V) neon

A) II and V
B) I and IV
C) I, II, and III
D) III, IV, and V

Chemistry
2 answers:
lbvjy [14]4 years ago
5 0
Refer to the table below. Credits to https://terpconnect.umd.edu/~wbreslyn/chemistry/naming/IonicCharge2.jpg 

Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion.  We're looking for the ions that loses electrons here. So, from the table: 

Al 3+ , S 2- , O 2-, Ag + , Ne ( noble gas, no charge) 

Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.

Serjik [45]4 years ago
5 0
The answer to this question would be
B) I and IV
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According to the United States Department of Agriculture (USDA), Texas had 4 , 015 , 000 beef cows in 2013 . If one cow produces
marishachu [46]

Answer:

3.00 × 10¹¹ g

Explanation:

According to the United States Department of Agriculture (USDA), Texas had 4,015,000 beef cows in 2013. One beef cow produces 205 grams of methane per day. The methane produced by the beef cows in Texas per day is:

4,015,000Cow \times \frac{205gCH_4}{cow \times day} = \frac{8.23 \times 10^{8}gCH_4}{day}

Each year has 365 days. The methane produced by the beef cows in Texas per year is:

\frac{8.23 \times 10^{8}gCH_4}{day} \times \frac{365day}{1y} = 3.00 \times 10^{11}gCH_4

5 0
4 years ago
What is the density of an object with 525 grams and a volume of 15cm3?
Hunter-Best [27]

Answer: 35 g/cm

Explanation:

Density equals mass over volume. 525 divided by 15 is 35

7 0
3 years ago
Read 2 more answers
Consider a sample of calcium carbonate in the form of a cube measuring 2.805 in. on each edge.
Naya [18.7K]

Answer:

The answer to your question is: 8.82 x 10 ²⁴ atoms of oxygen          

Explanation:

Data

Cube measuring : 2.805in on each edge

density = 2.7 g/cm3

# of oxygen atoms in the cube = ?

Process

Volume of the cube = (2.805)³ = 22.07 in³

Convert in³ to cm³                  1 in³   -------------------  16.39 cm³

                                       22.07 in³    --------------------    x

                        x = (22.07 x 16.39) / 1 = 361.72 cm³

Density = mass / volume

Mass = density x volume

Mass = (2.7)(361.72) = 976.66 g

Atomic mass CaCO3 = 40 + 12 + (16 x 3) = 100 g

                                100 g of CaCO3 --------------------  48 g of O2

                                976.66 g of CaCO3 ---------------    x

                           x = (976.66 x 48) / 100 = 468.8 g of O2

                              32 g of O2 ----------------------  1 mol

                           468.8 g of O2 --------------------   x

                       x = (468.8 x 1) / 32 = 14.65 mol

                           1 mol -----------------------   6.023 x 10 ²³ atoms

                        14.65 mol -------------------    x

                    x = (14.65 x 6.023 x 10 ²³) / 1 = 8.82 x 10 ²⁴ atoms of oxygen          

3 0
3 years ago
I need a background information for this lab report if anyone could help me please :((( it's due tomorrow
UkoKoshka [18]
So the whole point is that you need a abstract.
7 0
3 years ago
Which of the following is the correct definition of density?
egoroff_w [7]

Answer:

3

Explanation:

The amount of mass per given vol

5 0
3 years ago
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