Ionic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in t
he process of forming an ionic bond. Nonmetals, such as chlorine, tend to gain valence electrons in the formation of ionic bonds.
Determine which element(s) are likely to have their electrons stripped away in the formation of ionic bonds. I) aluminum II) sulfur III) oxygen IV) silver V) neon
A) II and V
B) I and IV
C) I, II, and III
D) III, IV, and V
Determine which element(s) are likely to have their electrons stripped away in the formation of ionic bonds. I) aluminum II) sulfur III) oxygen IV) silver V) neon
A) II and V
B) I and IV
C) I, II, and III
D) III, IV, and V
2 answers:
Refer to the table below. Credits to https://terpconnect.umd.edu/~wbreslyn/chemistry/naming/IonicCharge2.jpg
Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion. We're looking for the ions that loses electrons here. So, from the table:
Al 3+ , S 2- , O 2-, Ag + , Ne ( noble gas, no charge)
Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.
Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion. We're looking for the ions that loses electrons here. So, from the table:
Al 3+ , S 2- , O 2-, Ag + , Ne ( noble gas, no charge)
Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.
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