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To find the number of atoms in 2.822 moles of nickel, we need to multiply it by Avogadro's number. Avogadro's number is 6.02 x 10^23 atoms.
2.822 moles x (6.02 x 10^23) ≈ 1.698844 x 10^24
Therefore, there are about 1.70 x 10^24 atoms (according to the number of significant figures) in 2.822 moles of nickel.
Answer:
2.12atm
Explanation:
Boyle's Law: P1V1 = P2V2
Manipulate to solve for unknown: P2 = P1V1/V2
Substitute values: P2=(1.2atm)(4.6L)/2.6L
P2 = 2.1230769atm
Round to 3 sig figs to get 2.12atm
Answer:
1 mole of Al2O3 = 102 grams
1 mole of Al2 = 54 grams
102 grams of Al2O3 contains = 54 gram of Al2
10kg of Al2O3 contains = (54/102)*10000g Al2
= 5294.11 g Al2 or 5.29411 kg
Answer : The number of molecules present in nitrogen gas are,
Explanation :
First we have to calculate the moles of nitrogen gas by using ideal gas equation.
where,
P = Pressure of
gas =
(1 atm = 760 mmHg)
V = Volume of
gas = 985 mL = 0.982 L (1 L = 1000 mL)
n = number of moles
= ?
R = Gas constant =
T = Temperature of
gas =
Now put all the given values in above equation, we get:

Now we have to calculate the number of molecules present in nitrogen gas.
As we know that 1 mole of substance contains
number of molecules.
As, 1 mole of
gas contains
number of molecules
So,
mole of
gas contains
number of molecules
Therefore, the number of molecules present in nitrogen gas are,