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2 years ago

I need the answers ASAP •_•

Mathematics

1 answer:

Cloud [144]2 years ago

7 0

Answer:

17) vertical

18) vertical

19) vertical

20) adjacent

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A Boston subway train traveling at constant speed traveled 10.1 miles in half an hour. What was the speed of the subway train? m

viva [34]

Answer: 20.2 mph

Step-by-step explanation:

Given

Train travels 10.1 miles in half an hour i.e.

Distance $d=10.1\ \text{miles}$

time $t=0.5\ hr$

we know, $\text{distance=speed}\times\text{time}$

Insert the values

$\Rightarrow 10.1=v\times 0.5\\\Rightarrow v=20.2\ mph$

6 0

2 years ago

PLZ HELP MEEEE!!

arsen [322]

Answer:

42x+6y>24

Step-by-step explanation: im sorry if i am wrong but i belive that is correct

6 0

1 year ago

Root 8 + 3 root 32 - root 50

lisov135 [29]

$\sqrt{8} + 3 \sqrt{32} - \sqrt{50}$

$= \sqrt{4 \times 2} + 3 \sqrt{16 \times 2} - \sqrt{25 \times 2}$

$= 2\sqrt{ 2} + 12 \sqrt{2} - 5\sqrt{ 2}$

$= 9\sqrt{ 2}$

6 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

I need help, do I have these pink dots in the right place?

irakobra [83]

Answer:

no, you actually don't.

Step-by-step explanation:

remember: x is how many to the left, and y is how many to the top.

reposition the dots and I will see if it is right the 2nd time.

hope this helped!

6 0

2 years ago

Read 2 more answers