Answer:
2.3125g
Explanation:
Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.
Given:
t(1/2)= 9.25days
Initial mass of Thulium-167 = 48grams
We need to calculate the remaining amount after 37days.
Since we know that 1 half life = 9.25 days
Then 37 days means ( 37/9.25) half lives
37days means 4 half life
That means the 38grams of Thulium-167 will be halved by 4 times.
Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)
= 37days × 0.5^(4)
= 2.3125g
the remaining amount of Thallium-167 after 37days is 2.3125g
Answer:
9.92
Explanation:
Since we are given the concetration of H+ we can find the ph by taking the negative log and then subtracting the ph from 14 to give us pOH
-log(8.26e-5) = pH= 4.08
pOH= 14-4.08
pOH= 9.92
Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
Answer:
The value is 
Explanation:
From the question we are told that
mass of carbon dioxide produced by one gallon of gasoline is 
The number of cars is 
The distance covered by each car is 
The rate is 
Generally the amount of gasoline used by one car is mathematically represented as
=> 
=> 
Generally the amount of gasoline used by N cars is
=> 
=> 
Generally the annual production of carbon dioxide is mathematically represented as
=> 
=>
The electron dot structure for each molecule are:
.. ..
a. H:O:O:H
.. ..
The partial negative charges are on the Oxygen atoms.
..
b. H:Cl:
..
The partial negative charge is on the Chlorine atom.
..
c. H:Br:
..
The partial negative sign is on Bromine atom.
..
d. H:O:H
..
The partial negative sign is on the Oxygen atom.
