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skad [1K]
3 years ago
9

How many moles of N2O5 are needed to produce 7.90 g of NO2? 2N2O5 = 4NO2 + O2

Chemistry
2 answers:
Annette [7]3 years ago
4 0

Answer: 0.08585 moles of N_2O_5 is needed to produce 7.9 grams of NO_2

Explanation: Moles is calculated by using the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of NO_2 = 46 g/mol

Number of moles of NO_2=\frac{7.9g}{46g/mol} = 0.1717 moles

For the given chemical reaction:

2N_2O_5\rightarrow 4NO_2+O_2

By Stoichiometry,

4 moles of NO_2 is produced by 2 moles of N_2O_5

So, 0.1717 moles of NO_2 is produced by = \frac{2}{4}\times 0.1717 = 0.08585 moles of N_2O_5

Hence, moles of N_2O_5 is 0.08585 moles.

miv72 [106K]3 years ago
3 0
Moles of N2O5 = moles of NO2 * ( 2 moles of N2O5 / 4 moles of NO2
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