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Airida [17]
3 years ago
15

1.

Chemistry
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

i think it would be A

Explanation:

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What does it mean for a element of a group to have a order?
lisabon 2012 [21]

In group theory, a branch of mathematics, the term order is used in two unrelated senses:

<span><span>The order of a group is its cardinality, i.e., the number of elements in its set. Also, the order, sometimes period, of an element a of a group is the smallest positive integer m such that <span>am = e</span> (where e denotes the identity element of the group, and am denotes the product of m copies of a). If no such m exists, a is said to have infinite order.</span><span>The ordering relation of a partially or totally ordered group.</span></span>

This article is about the first sense of order.

The order of a group G is denoted by ord(G) or | G | and the order of an element a is denoted by ord(a) or | a |.

8 0
4 years ago
Which of the following should have the largest Henry's law constant (kH) in water?
Ostrovityanka [42]

Answer: Option (B) is the correct answer.

Explanation:

It is known that Henry's law is a relation between the concentration of a gas in a liquid (solubility) and the pressure it exerts on the surface of the liquid.

According to Henry's law, the pressure of a gas is directly proportional to the solubility of the gas in a liquid.

Henry's constant is represented by the symbol K_{H}. And, mathematically it is represented as follows.

                      P = K_{H}C  

where,      P = pressure and C = solubility

As the pressure for the given species is the same. Hence, the standard values of solubility of the given species is as follows.

               Gas           Solubility

                Ar          3.025 \times 10^{-5}

               CO         2.095 \times 10^{-5}

               Xe         10.519 \times 10^{-5}

            CH_{3}CH_{3}   4.556 \times 10^{-5}

              CO_{2}   8.21 \times 10^{-4}

As, Henry's constant is inversely proportional to the solubility. Hence, more is the value of solubility lesser will be the value of Henry's constant.

Thus, we can conclude that out of the given options CO have the largest Henry's law constant (K_{H}) in water.

6 0
3 years ago
How are the isotopes of a particular element alike?
zhannawk [14.2K]
The isotopes of a particular elements means that every element has there own isotopes like H has three isotopes protium, dutrium,tritium. like that cl has also thier own isotopes.
6 0
3 years ago
A student used 10mL water instead of 30mL for extraction of salt from mixture. How may this change the percentage of NaCl extrac
34kurt
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:

360 g : 1 L = x g : 30 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000 
x = 10.8 g

So, from 30 mL mixture, 10.8 g of NaCl could be extracted.

Let's calculate the same for 10 mL water instead of 30 mL.

360 g : 1 L = x g : 10 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL

Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000 
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3

Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.
</span>
7 0
3 years ago
How does the oxidation state of O change in the following reaction?
Liula [17]

Answer:

Oxygen Doesn't change

However, Li is oxidized (0 to +1), Na is reduced (+1 to 0)

Explanation:

On reactant side, Oxygen has -2 oxidation charge because we know common oxidation states such as oxygen -2, hydrogen +1 etc.

So NaOH, O is -2, H is +1, so Na has to be +1 to equal total charge of compound

In product side, LiOH, again O has to be -2, H is +1, so Li +1 as well..

We see that oxygen oxidation state doesn't change. However, for Li it becomes oxidized going from 0 to +1 whereas, Na is reduced going from +1 to 0.

8 0
3 years ago
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