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g100num [7]
3 years ago
15

Apakah biodiversiti ? ​

Chemistry
1 answer:
inna [77]3 years ago
6 0
Biodiversiti adalah kehidupan di dunia termasuk manusia, hewan dan tumbuhan
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A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

Substitute the values into the formula:

​p = \frac{16.59 g}{5.81 mL} \\   = 2.8554 g/mL

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0
2 years ago
Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0
3 years ago
Which type of reaction does this diagram represent?
Mice21 [21]
I want to say addition. But I have a tendency to be wrong

8 0
4 years ago
Read 2 more answers
Which of the following is true for compounds?
Anuta_ua [19.1K]
What are the following?
6 0
3 years ago
A laboratory procedure calls for making 590.0 mL of a 1.1 M KNO3 solution. How much KNO3 in grams is needed?
AveGali [126]
590 mL = 590 cm³= 0,59 dm³

C = n/V
n = 1,1M × 0,59 dm³
n = 0,649 mol
_____________________________

M KNO₃ = 39g+14g+16g×3 = 101 g/mol

1 mole -------- 101g
0,649 --------- X
X = 101×0,649
X = 65,549g KNO₃

:)
8 0
3 years ago
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