Sodium Na is a metal that belong to the alkali metal with low density and soft
The change in temperature of the metal is 6.1°C. Details about change in temperature can be found below.
<h3>How to calculate change in temperature?</h3>
The change in temperature of a substance can be calculated by subtracting the initial temperature of the substance from the final temperature.
According to this question, a 25.0 g sample of metal at 16.0 °C is warmed to 22.1 °C by 259J of energy.
This means that the change in temperature of the metal can be calculated as:
∆T = 22.1°C - 16°C
∆T = 6.1°C
Therefore, the change in temperature of the metal is 6.1°C.
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Answer:
The correct answer is option false.
Explanation:
Molality of the solution defined as moles of substance present in 1 kilogram of solvent.
Moles = 
Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.
So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.
Mass of solution = Mass of solute + Mass of solvent
Answer:-
0.633 moles
Explanation:-
The first step to solving this problem is to write the balanced chemical equation.
The balanced chemical equation for this reaction is
3 CaCO3 + 2 FePO4 = Ca3(PO4)2 + Fe2(CO3)3
From the balanced chemical equation, we can see
3 moles of CaCO3 react with 2 moles of FePO4.
In the question we are told there are 1.9 moles of CaCO3.
So 1.9 moles of CaCO3 react with (2 moles x 1.9 moles )/ 3 moles= 1.267 moles of FePO4.
The question tells us there are 2.7 moles of FePO4.
So there is excess FePO4.
Thus our limiting reagent is CaCO3. It will determine how much Ca3(PO4)2 is formed.
From the balanced chemical equation, we can see
3 moles of CaCO3 gives 1 mole of Ca3(PO4)2
1.9 moles of CaCO3 gives (1 moles x 1.9 moles ) / 3 moles= 0.633 moles of Ca3(PO4)2.
0.633 moles of Ca3 (PO4)2 can be formed when 1.9 moles of CaCO3 react with 2.7 moles of FePO4
