You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:
Runner distance time
Arabella 7,299 feet 561 seconds
Bettina 3,425 yards 13 minutes, 12 seconds
Chandra 8,214 feet 0,195 hours
Divya 1,62 miles 732 seconds
To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.
First you need to convert the data to obtain the rate in miles per second.
These are the main conversion identities:
1 mile = 5280 feet
1 mile = 1760 yards
1 hour = 3600 seconds
1 hour = 60 minutes
1 minute = 60 seconds
Arabella:
rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet) =
= 0.00244 mile/second
Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds
Bettina:
13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds
rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds
Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds
Chandra:
rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =
= 0.00222 seconds
Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds
Divya:
rate = 1.62 miles / 732 seconds = 0.00221 seconds
Time = 3.1 mile / 0.00221 seconds = 1403 seconds
Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds
That is equivalent to 2.38 seconds.
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
23:44 or 1:1.91
Step-by-step explanation:
w:l =69:132 Divide each number by 3
= 23:44 Divide each number by 23
≈ 1:1.91
The width-to-length ratio is 23:44 or approximately 1:1.91
Answer:
(a) 1.5 inches
(b) 2.5 inches
(c) 5 inches
Step-by-step explanation:
speed of first turtle = 4 1/2 inches per minute = 9/2 inches per minute
speed of the second turtle = 5inches per minute
distance = speed x time
(a) Distance traveled by first turtle in 3 minutes
s = 9/2 x 3 = 13.5 inches
distance traveled by second turtle in 3 minutes
s' = 5 x 3 = 15 inches
So, the gap is
s'- s = 15 - 13.5 = 1.5 inches
(b) Distance traveled by first turtle in 5 minutes
s = 9/2 x 5 = 22.5 inches
distance traveled by second turtle in 5 minutes
s' = 5 x 5 = 25 inches
So, the gap is
s'- s = 25 - 22.5 = 2.5 inches
(c) Distance traveled by first turtle in 10 minutes
s = 9/2 x 10 = 45 inches
distance traveled by second turtle in 10 minutes
s' = 5 x 10 = 50 inches
So, the gap is
s'- s = 50 - 45 = 5 inches
Answer:
Your answer is correct. The series is a geometric series with common ratio -1/4 and first term 40. So each term is:
an = 40 (-1/4)^(n−1)
So the sum of the first 10 terms is:
∑(n=1 to 10) [ 40 (-1/4)^(n−1) ]
