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mel-nik [20]
3 years ago
13

WILL MARK BRAINLIEST!!!!

Mathematics
2 answers:
Ber [7]3 years ago
8 0

Answer:

Step-by-step explanation:

2x-3

2(21)-3

42=3

39

svetlana [45]3 years ago
6 0

Answer:

its 5

3(2x-3)=21

6x-9=21

6x=30

x=5

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What is the approximate circumference of a circle with a radius of 18 feet?
klio [65]

Answer:

The answer is

<h2>113 feet </h2>

Step-by-step explanation:

Circumference of a circle is 2πr

where r is the radius

From the question

r = 18 feet

Circumference of the circle is

2π(18)

= 36π

= 113. 09

= 113 feet

Hope this helps you

7 0
3 years ago
Read 2 more answers
Graph y= 2x-2 with the domain (1,2,3)
Mamont248 [21]
Graph attached. 
To graph by hand find the values at 1 and 3 by plugging it into the original function and drawing a line between the two.
2(1)-2 = 0     Point  (1,0)
2(3)-2 = 4     Point  (3,4)


3 0
3 years ago
What areC12, C31, and C22 of matrix C?
Liono4ka [1.6K]

Compute the sum to simplify C :

C = \begin{bmatrix}16-0.5 & 9+0 \\ -3+5 & 0 + 8 \\ 4-3 & -10+14\end{bmatrix} = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ 1 & 4\end{bmatrix}

Now, c_{ij} is the entry of the matrix in row i and column j, so

C = \begin{bmatrix}15.5 & \boxed{9} \\ 2 & 8 \\ 1 & 4\end{bmatrix} \implies c_{12} = 9

C = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ \boxed{1} & 4\end{bmatrix} \implies c_{31} = 1

C = \begin{bmatrix}15.5 & 9 \\ 2 & \boxed{8} \\ 1 & 4\end{bmatrix} \implies c_{22} = 8

5 0
2 years ago
Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?
Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

f(x) = \dfrac{2}{x - 1} + 4

From the given function, we have;

When x = 1, the denominator of the fraction, \dfrac{2}{x - 1}, which is (x - 1) = 0, and the function becomes, \dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as <em>x</em> increases, the fraction \dfrac{2}{x - 1} tends to 0, therefore as x increases, we have;

\lim_  {x \to \infty}  \dfrac{2}{(x - 1)} \to 0, and \  \dfrac{2}{(x - 1)}  + 4 \to 4

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, \dfrac{2}{0 - 1} + 4 = 2. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

5 0
3 years ago
Drag each scenario to show whether the final result will be greater than the original
Hoochie [10]

A $20 decrease followed by a $20 increase - original value

A 75% decrease followed by a 50% increase - less than the original value

A 50% increase followed by a 33 1/3% decrease - greater than the original value

A 60% increase followed by a 40% decrease - greater than the original value

A 100% increase followed by a 33 1/3% decrease - greater than the original

7 0
3 years ago
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