The full ionic equation for the conversion of aqueous lead (II) nitrate to solid lead (II) sulfate and aqueous potassium nitrate is as follows:
<h3>What is
ionic equation ?</h3>
PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and SO42(aq) (aq)
Let's look at the molecular formula that results in solid lead (II) sulfate and aqueous potassium nitrate when aqueous lead (II) nitrate and aqueous potassium sulfate interact. This reaction involves two displacements.
PbSO4(s) + 2 KNO3 = Pb(NO3)2(aq) + K2SO4(aq) (aq)
All ions and molecular species are included in the full ionic equation.
PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and SO42(aq) (aq)
The full ionic equation for the conversion of aqueous lead (II) nitrate to solid lead (II) sulfate and aqueous potassium nitrate is as follows:
PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and SO42(aq) (aq)
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Answer:
pH = 2.66
Explanation:
weak acid:
∴ Ka = 5 E-5 M = [H+][A-]/[HA]
∴ [HA] = 0.10 M - [A-]
∴ [H+] = [A-]
⇒ Ka = [H+]²/(0.10 - [H+])
⇒ [H+]² + 5 E-5[H+] - 5 E-6 = 0
⇒ [H+] = 2.211 E-3 M
⇒ pH = - Log [H+]
⇒ pH = 2.6553
Answer:
An F1 offspring could produce four types of gametes, RY, Ry, rY, and ry. The F2 generation supports the independent-assortment model and refutes the linkage model.
Explanation:
Answer:
Na - 1 away from neon
Li - 1 away from helium
K - 1 away from argon
Cs - 1 away from xenon
Explanation:
We see this trend as group 1A elements are 1 away from noble gases and hence, have a valency of 1
384.72 J is the heat of fusion of the substance.
<h3>What is the heat of fusion? </h3>
It is the change in the value of the enthalpy by providing energy i.e. heat, for a specific quantity of the substance.
Given data:
Heat of fusion =?
Mass of substance = 8.4 g
Unknown:
Amount of energy required to melt the given mass = 45.8 cal
Solution:
To solve this problem, the amount of energy required to melt the substance is given as;
H = m L
m is the mass
L is the heat of fusion
Insert the given parameters and solve;
H = 8.4 g x 45.8 cal = 384.72 J
Hence, 384.72 J is the heat of fusion of the substance.
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