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Digiron [165]
3 years ago
6

Gets their food by braking dead material?

Chemistry
1 answer:
Verdich [7]3 years ago
3 0
Decomposers. they decompose or break down material  
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The energy associated with motion is
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Yes the answer is a , kinetic energy
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ANSWER ASAP GIVING BRAINIEST FIVE STARS AND HEART!
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Law of conservation of matter: It is the principle that matter can not be destroyed or created and we have a finite and limit amount of matter in the universe.
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Do you think naturally produced antimicrobial products like nisin and natamycin should replace sorbic acid for food preservation
saul85 [17]

Answer:

No.

Explanation:

change is often not rational.

7 0
3 years ago
Limestone (CaCO3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be p
Harman [31]

Answer: 2800 g

Explanation:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5 kg = 5000 g

\text{Number of moles}=\frac{5000g}{100g/mol}=50moles

1 mole of CaCO_3 produces = 1 mole of CaO

50 moles of CaCO_3 produces =\frac{1}{1}\times 50=50moles of CaO

Mass of CaO=moles\times {\text{Molar mass}}=50moles\times 56g/mole=2800g

2800 g of CaO is produced from 5.0 kg of limestone.

3 0
3 years ago
A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change
MrRa [10]

Answer:

-54 kJ/mol

Explanation:

Given that:

A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol

i.e

50 ml of 1.0 M HCl +  50 ml of 1.0 M NaOH -----> -54 kJ/mol

If he repeat the same experiment with :

100 ml of 1.0 M HCl + 100 ml of 1.0 M NaOH. ------> ????

From The experiment; the molar enthalpy of change of the acid-base neutralization reaction will be -54 kJ/mol

This is because : The second reaction requires 50 ml in order to neutralize the reaction, then the remaining 50 ml will be excess, Hence, there is no change in the enthalpy of the reaction.

Similarly; we can assume that :

In the first reaction;  P moles of  is used to liberate Q kJ heat ; then  the change in molar enthalpy will be Q/P (kJ/mol).

SO; when he used 100 ml ;

then the amount of moles used is double, likewise the heat liberated will be doubled ;

So;

2P moles is used to liberate 2Q kJ heat ;

2P/2Q = Q/P ( kJ/mol) = -54 kJ/mol

8 0
3 years ago
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