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sashaice [31]
3 years ago
9

For the data set 3 7 5 8 4 7 5 9 4 7 6 11 4 7 6 12 4 7 6 16 5 8 7 25 Send data to Excel Part 1 of 4 Your Answer is correct (a) F

ind the first and third quartiles. The first quartile is 5. The third quartile is 8. Part: 1 / 41 of 4 Parts Complete Part 2 of 4 (b) Find the IQR.
Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

Answer to For the data set 7 9 6 4 6 6 25 8 12 7 7 11 4 7 5 16 4 5 4 5 3 7 7 8 Send data to Excel Part: 0 / 4 Part 1 of 4 (a)

Step-by-step explanation:

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What is the surface area of the prism<br><br> A. 812<br> B. 1,190<br> C. 2,352<br> D. 132
seropon [69]

Answer:

B. 1,190 square cm

Step-by-step explanation:

For given prism:

l = 16 cm, w = 7 cm, h = 21 cm

Surface area of of the prism

= 2 (lw + wh + hl)  \\  = 2(16 \times 7 + 7 \times 21 + 21 \times 16) \\  = 2(112 + 147 + 336) \\  = 2 \times 595 \\  = 1190 \:  {cm}^{2}  \\

4 0
3 years ago
Can you help me show the work and give me the answer?
Murrr4er [49]
The total distance must be greater than 80.  She has already ridden 18 miles.  And she will continue to ride m miles per day for at least 6 more days, so:

6m+18>80

More "work"...

distance>80

distance=18+6m

6m+18>80
7 0
3 years ago
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\&#10;\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
I need to find the area below! <br> HELP!
Evgen [1.6K]
Area of the square: 8x7 = 56
Base of triangle: 3+8+3 = 14
Height of triangle: 12-7 = 5
Area of triangle: 1/2(14)(5) = 35
Area of both: 56 + 35 = 91 in.
6 0
3 years ago
A circular park has a circumference of 36 yd. find its diameter​
tamaranim1 [39]

Answer:

412.53 inches

or

11.45916 yards

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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