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2 years ago

What is the probability that Someone in your class will have a pet alligator?

Mathematics

1 answer:

wel2 years ago

5 0

Answer:

Zero

Thank you answer above .

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Help solve algebra 15a=6a-90

AleksandrR [38]

15a =6a - 90

Move all the numbers with variables to one side

15a - (6a) = 6a -(6a) -90
9a = -90
9a/9 = -90/9
a = -9

Hope this helps

5 0

2 years ago

A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly se

Darina [25.2K]

Answer: (17.42, 20.78)

Step-by-step explanation:

As per given , we have

Sample size : n= 9

$\overline{x}=19.1$ years

Population standard deviation is not given , so it follows t-distribution.

Sample standard deviation : s= 1.5 years

Confidence level : 99% or 0.99

Significance level : $\alpha= 1-0.99=0.01$

Degree of freedom : df= 8 (∵df =n-1)

Critical value : $t_c=t_{(\alpha/2,\ df)}=t_{0.005,\ 8}= 3.355$

The 99% confidence interval for the population mean would be :-

$\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}$

$19.1\pm (3.355)\dfrac{1.5}{\sqrt{ 9}}\\\\=19.1\pm1.6775\\\\=(19.1-1.6775,\ 19.1+1.6775)\\\\=(17.4225,\ 20.7775)\approx(17.42,\ 20.78)$

Hence, the 99% confidence interval for the population mean is (17.42, 20.78) .

7 0

2 years ago

Find the range of f(x)=-2x+6 for the domain {-1, 3, 7, 9}

velikii [3]

Answer:

8, 0, -8, -12

Step-by-step explanation:

3 0

3 years ago

What is the area of this figure?<br> 168<br> 102<br> 132<br> 340

JulsSmile [24]

Area of square =6*6= 36 cm^2
Area of trapezoid =1/2( base1+base2)*height
base 1=7
base2=21-6=15
height=6
Area of trapezoid =1/2( 7+15)*6= 66
whole area = area of square + area of trapezoid= 36+66=102
Answer 102

8 0

2 years ago

If 3 + root8 by 3-root8 + 3-root8 by 3+root8 = a+broot2 find a and b

s2008m [1.1K]

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables or numbers.

$\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8 }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}$

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

1 year ago