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Vadim26 [7]
3 years ago
6

Melissa has more than 40 coins in her collection which inequality the nuber of coinsin melissas collection

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

X > 40

Step-by-step explanation:

Given that:

Let number of coins in her collection is more Than 40

To represent the number of coins in Melissa's collection as an inequality :

Let total number of items in her collection = X

Coins in her collection > 40

Hence, coins in her collection can be represented as :

X > 40

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In order to calculate rate or average speed you divide miles by time

I got 153.8 by dividing 500 by 3.25 (the .25 is because 15 minutes is 1/4 of 60) hope this helped!!
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3 years ago
A right circular cylinder has a height of 22 1/4 ft and a diameter 2 2/5 times its height. What is the volume of the cylinder? E
Triss [41]

Answer:

The volume of cylinder is:

49806.06 ft^3

Step-by-step explanation:

We are given a right circular cylinder with:

Height(h)=22\frac{1}{4}ft=\dfrac{89}{4}ft

and a diameter is 2\frac{2}{5} times it's height.

i.e. \dfrac{12}{5} times it height.

i.e. the diameter is given as:

\dfrac{12}{5}\times \dfrac{89}{4}=\dfrac{267}{5}ft.

We know that the radius of cylinder is half the diameter.

Hence, radius(r) of cylinder is:

\dfrac{1}{2}\times \dfrac{267}{5}\\\\=\dfrac{267}{10}

The volume(V) of cylinder is given by:

V=\pi r^2h

V=3.14\times (\dfrac{267}{10})^2\times \dfrac{89}{4}\\\\V=\dfrac{19922423.94}{400}\\\\V=49806.06ft^3

Hence, the volume of cylinder is:

49806.06 ft^3

7 0
4 years ago
What is the interquartile range of this data 0 5 10 15 20​
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The interquartile range (IQR) is 15.

To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
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3 years ago
Please help me with this
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4 0
3 years ago
What size does the radius of a sphere need to be for its volume to be larger than its surface area? HINT! It is less than 10. HI
Lera25 [3.4K]
We know that
volume of a sphere=(4/3)*pi*r³----> (r/3)*(4*pi*r²)
and
surface area of sphere=4*pi*r²
so
the volume of a sphere=(r/3)*surface area of sphere
therefore
if r=3
volume of a sphere=(3/3)*surface area of sphere
volume of a sphere=surface area of sphere

if r> 3
the term (r/3) is > 0
so
volume of a sphere > surface area of sphere

if r<3
the term (r/3) is < 0
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examples
1) for radius r=3 units
volume of a sphere=(4/3)*pi*3³----> 113.04 unit³
surface area=4*pi*3²----> 113.04 units²
volume is equal to surface area

2) for radius r=10 units
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surface area=4*pi*10²----> 1256 units²
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3) for radius r=2 units
volume of a sphere=(4/3)*pi*2³----> 33.49 unit³
surface area=4*pi*2²----> 50.24 units²
volume is <  surface area
7 0
3 years ago
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