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kotegsom [21]
3 years ago
7

Which land forms are formed by wind deposition in the desert region?​

Mathematics
2 answers:
Elena L [17]3 years ago
8 0

Answer:

Sand Dune Landforms

Sand dunes (both active and stabilized by vegetation) can be found along beaches, and in arid or semi-arid regions. Dunes are mounds of loose sand created by wind and are the most well known aeolian features

Jet001 [13]3 years ago
8 0

Answer:

In deserts, wind picks up small particles and leaves behind larger rocks to form desert pavement.  Moving sand may sandblast rocks and other features to create ventifacts.  The sand is transported until it is deposited in a sand dune

hope this helped in a way lol :)

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Anvisha [2.4K]

Answer:

Step-by-step explanation:

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Write following ratio in simplest form : <br> 125 g : 1 kg​
Dmitry [639]

Answer:

125g:1Kg

=> 125g : 1000g

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A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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Hello!

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60% / 100 = 0.60

20% / 100 = 0.20

Then, we multiply 0.60 and 0.20 by 20.

0.60 x 20 = 12

0.40 x 20 = 8

Therefore, Adi gets 12 chocolates and Suresh gets 8 chocolates.

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