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2 years ago

Which land forms are formed by wind deposition in the desert region?

Mathematics

2 answers:

Elena L [17]2 years ago

8 0

Answer:

Sand Dune Landforms

Sand dunes (both active and stabilized by vegetation) can be found along beaches, and in arid or semi-arid regions. Dunes are mounds of loose sand created by wind and are the most well known aeolian features

Jet001 [13]2 years ago

8 0

Answer:

In deserts, wind picks up small particles and leaves behind larger rocks to form desert pavement. Moving sand may sandblast rocks and other features to create ventifacts. The sand is transported until it is deposited in a sand dune

hope this helped in a way lol :)

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For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c

Illusion [34]

Answer: Our required equation would be $6=\dfrac{c}{2}+1$

Step-by-step explanation:

Since we have given that

Amount that Anderson earns per hour = $6

According to question, Anderson earns $1 more than half of Carey's hourly rate.

Let the hourly rate of Carey be 'c'.

So, it becomes,

$6=\dfrac{c}{2}+1$

And the value of c would be

$6=\dfrac{c}{2}+1\\\\6-1=\dfrac{c}{2}\\\\5=\dfrac{c}{2}\\\\c=\$10$

Hence, our required equation would be $6=\dfrac{c}{2}+1$

5 0

3 years ago

A new club sent out 288 coupons to boost sales for next year's memberships. They provided 5 times as many to potential members t

Aliun [14]

Answer:

D. 48

Step-by-step explanation:

We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.

They sent 5 times as many coupons to potential members as they did to existing members.

Let x = number of coupons sent to existing members.

Then 5x = number of coupons sent to potential members.

The total number of coupons sent was x + 5x = 6x

The total number of coupons sent was 288.

Therefore, 6x must equal 288 giving us an equation with a single variable.

6x = 288

x = 48

Answer: 48

7 0

2 years ago

Find the dot product of the position vectors whose terminal points are (14, 9) and (3, 6).

erma4kov [3.2K]

Answer:

Step-by-step explanation:

The formula for the dot product of vectors is

u·v = |u||v|cosθ

where |u| and |v| are the magnitudes (lengths) of the vectors. The formula for that is the same as Pythagorean's Theorem.

$|u|=\sqrt{14^2+9^2}$ which is $\sqrt{277}$

$|v|=\sqrt{3^2+6^2}$ which is $\sqrt{45}$

I am assuming by looking at the above that you can determine where the numbers under the square root signs came from. It's pretty apparent.

We also need the angle, which of course has its own formula.

$cos\theta=\frac{uv}{|u||v|}$ where uv has ITS own formula:

uv = (14 * 3) + (9 * 6) which is taking the numbers in the i positions in the first set of parenthesis and adding their product to the product of the numbers in the j positions.

uv = 96.

To get the denominator, multiply the lengths of the vectors together. Then take the inverse cosine of the whole mess:

$cos^{-1}\theta=\frac{96}{111.64676}$ which returns an angle measure of 30.7. Plugging that all into the dot product formula: