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Nonamiya [84]
2 years ago
15

Will Mark branliest! :) (At the end it says round the the nearest tenth) thank you!

Mathematics
2 answers:
Finger [1]2 years ago
6 0

Answer:

538,3m^2

Step-by-step explanation:

first of all, I find it really disturbing to use 3,14 as pi but I'll try my best.

1) Determine the area of the rectangle;

h.b= area of a rectangle

so here

15m.30m = 450 m^2

the area of the circle = pi.r^2

so here

7,5m^2.3,14 = 176,625m^2

but we only need the half of it so 176,625m^2/2 = 88,3125m^2 ~ 88,3m^2

then we must sum them all up;

88,3m^2 + 450m^2 = 538,3m^2

Jobisdone [24]2 years ago
3 0

Answer:

B

Step-by-step explanation:

20 x 15 is 450 and add it to the semi circle which us 88.4

Hope this helps u :D

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Please review the following attachment. Thanks!
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Answer:

C: I and III only.

Step-by-step explanation:

We have two numbers x and y such that:

-y

And we want to determine which of the following conditions must be true.

First, let's examine the third condition. We have:

y>0

To see if this is true, let's try a negative value for y. So, let's use -7. This will give:

-(-7)

Simplify:

7

This is saying we need a number less than -7 and greater than 7.

This is impossible. So, y <em>must be</em> greater than 0.

Therefore, Condition III must be true.

Next, let's see this compound inequality visually.

Picture the following number-line:

<----------(-y)----------0----------y---------->

Whatever y is, -y is just y on the negative side.

Now, since our condition is that -y<x<y, this means that our x can be anywhere between -y and y. Namely:

<----------(-y)----------0----------y---------->

To determine our correct condition, let's picture x anywhere on the bolded lines. I'm just going to put x here...

<----------(-y)-------(x)--0----------y---------->

Now, remember the alternative definition for absolute value. Namely, the absolute value of x is also the <em>distance</em> from 0 to x. And this distance is always positive.

Since our x is between -y and y, our distance from 0 to x will always be less than the distance from 0 to either y.

Therefore, Condition I is also true.

Let's try an example. Let's let y = 9. So, -y=-9. And let's let x be between 9 and -9, say, -2. So:

<---(-9)-----(-2)--0--------(9)------>

We can see that:

|-2|=2\stackrel{\checkmark}{

Also, this example counters Condition II, as our x can indeed be negative if we desire it.

Algebraically, if we have a negative x such that:  

-y

We can divide everything by -1 to obtain:

y>x>-y

We can flip this to get:

-y

Which is our original inequality. So, Condition II does not need to be true.

So, the two conditions that <em>must</em> be true is I and III.

So, our answer is C.

3 0
3 years ago
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