1.) Equal likely chance would be 50/50 for having a dog or a cat. There are 3 possibilities: one dog and one cat, 50%, two dogs, 25%, or two cats, 25%. Adding the probabilities of having two of the same pets would theoretically give you a 50% chance.
2.) If you used two coins to simulate the possible outcome of pets the family had, you would have two fair sided coins. Each coin would have one dog side and one cat side (or heads and tails, where you would assign each pet a side of the coin).
3.) You have to do the expirament on your own.
4.) Having three pets changes the probability to a 33.3% chance of having each pet. Using number one as an example, add the probabilities to get a 66.6% chance for having three of the same pets.
5.) You can change the simulation by using a 3-sided die.
Answer:
dilation
Step-by-step explanation:
Well, you didn't give an option to choose from. I know that the thing in the middle is a similar symbol. Dilations can prove that both shapes are similar. If LMN dilates to a smaller shape PQR then both shapes are SIMILLAR.
x - 2y + z = 5 | *2
⇒ 2x - 4y+ 2z=10
3x + 3y - 2z = - 6 } I sum up these relations
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2x+3x - 4y+3y+2z-2z=10-6
5x - y = 4 (1)
3x + 3y - 2z = - 6 | *3 ⇒ 9x + 9y - 6z = - 18
2x - y + 3z = 11 | *2 ⇒ 4x - 2y + 6z= 22 I sum up these
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⇒ 9x+4x+9y-2y-6z+6z= 4
13x+ 7y= 4 (2)
I write (1) and (2)
5x - y = 4 | *7
35x - 7y= 28
13x+7y=4
48x = 32
x= 32/48=4/6 ( 32:8=4, 48:8=6)
x= 2/3
5x-y=4,
5*2/3-y=4
y=10/3 -4=10/3-12/3=-2/3
⇒ y= - 2/3
x - 2y + z = 5
2/3 - 2*(-2/3)+z=5
2/3+4/3+z=5
6/3+z=5
2+z=5
z=3
x+y+z=2/3-2/3+3=3
x+y+z=3
Answer:
(0,8)
Step-by-step explanation:
That's the only one that is in both the red and orange parabola
It looks like the next six terms are 22, 26, 30, 34, 38, 42
It is increasing by 4
