Please help 20 pts marks brsinletsts

Mathematics

1 answer:

fgiga [73]3 years ago

6 0

Answer:

(0,8)

Step-by-step explanation:

That's the only one that is in both the red and orange parabola

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What is f(0) if f(t) = t^2 – 2t – 2?

Dafna11 [192]

Answer:

-2

Step-by-step explanation:

f(t) = t^2 – 2t – 2

To find f(0), replace t with 0 in the expression and evaluate the expression.

f(0) = 0^2 – 2(0) – 2

f(0) = -2

6 0

3 years ago

Read 2 more answers

Let f(x) = x + 8 and g(x) = x2 − 6x − 7. find f(g(2)). −7 −3 10 33 open study

Ray Of Light [21]

F(g(2))

g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
g(2) = 4 - 12 - 7
g(2) = -15

f(x) = x + 8
f(g(2) = f(-15) = -15 + 8 = -7 <==

ur answer is -7

6 0

3 years ago

What is the equation of the graph

AveGali [126]

Answer:

$y = 2x^2 + 1$

Step-by-step explanation:

The graph you see there is called a parabola. The general equation for the graph is as below

$y = a*x^2 + b$

To find the equation we need to find the constants a and b. The constant b is just how much we're lifting the parabola by. Notice it's lifted by 1 on the y axis.

To find a it's a little more tricky. Let's use the graph to find a value for a by plugging in values we know. We know that b is 1 from the previous step, and we know that when x=1, y=3. Let's use that!

$3 = a * (1)^2 + 1\\2 = a$