Question

How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —> 12CO2(g)+6H2O(g)+3909.9 kJ

Answer 1

Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

$2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)$

3909.9 kJ of of energy is produced by  = $15\times 22.4=336L$

100 kJ of oxygen gas are needed to produce = $\frac{336}{3909.9}\times 100=8.59L$