How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —> 12CO2(g)+6H2O(g)+3909
1 answer:
Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atmosphere respectively.
1 mole of every gas occupy volume at STP = 22.4 L
The balanced chemical reaction is:
3909.9 kJ of of energy is produced by =
100 kJ of oxygen gas are needed to produce =
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Answer:
0.86 g/mL
Explanation:
In order to solve the problem, you have to know the formula for "Density." Density refers to<em> </em><em>"mass per unit volume." </em><em>It's formula is:</em>
- <em>Density (ρ) = </em>
<em />
Next, we have to convert the units of measurement in accordance to what is being asked in the problem. It is asking for "g/mL," which means we have to convert 1.25 quarts<em> (qt.) </em>to mL and 2.25 pounds<em> (lbs.)</em> to grams.
Let's solve.
- 1 quart = 946.35 mL
1.25 qt. x =<em> 1,182.94 mL</em>
- 1 pound = 453.592 grams
2.25 pounds x = <em>1,020.58 grams</em>
Now that we converted them to their appropriate units of measurement, we can now solve for density.
- <em>ρ = </em>
- <em>ρ = </em>
<em />
- <em>ρ = 0.86 g/mL</em>
<em>The density of the motor oil is 0.86 g/mL</em>