Answer:
When an acid and a base are placed together, they react to neautralise the acid and base properties, thus making a salt.
Explanation:
The compound formed by the caption of the base and the anion of the acid is called a salt.
Answer:
6.52×10⁴ GHz
Explanation:
From the question given above, the following data were obtained:
Wavelength (λ) = 4.6 μm
Velocity of light (v) = 2.998×10⁸ m/s
Frequency (f) =?
Next we shall convert 4.6 μm to metre (m). This can be obtained as follow:
1 μm = 1×10¯⁶ m
Therefore,
4.6 μm = 4.6 μm × 1×10¯⁶ m / 1 μm
4.6 μm = 4.6×10¯⁶ m
Next, we shall determine frequency of the light. This can be obtained as follow:
Wavelength (λ) = 4.6×10¯⁶ m
Velocity of light (v) = 2.998×10⁸ m/s
Frequency (f) =?
v = λf
2.998×10⁸ = 4.6×10¯⁶ × f
Divide both side by 4.6×10¯⁶
f = 2.998×10⁸ / 4.6×10¯⁶
f = 6.52×10¹³ Hz
Finally, we shall convert 6.52×10¹³ Hz to gigahertz. This can be obtained as follow:
1 Hz = 1×10¯⁹ GHz
Therefore,
6.52×10¹³ Hz = 6.52×10¹³ Hz × 1×10¯⁹ GHz / 1Hz
6.52×10¹³ Hz = 6.52×10⁴ GHz
Thus, the frequency of the light is 6.52×10⁴ GHz
Answer:
Explanation:
Ratio of C : H : N : O in grams
= 72.15 : 7.08 : 4.68 : 16.03 in grams
Ratio of C : H : N : O in moles
72.15/12 : 7.08/1 : 4.68/14 : 16.03/16 in moles
6.01 : 7.08 : .334 : 1.00
6.01/ .334 : 7.08/.334 : .334/.334 : 1.00/.334 in moles
18 : 21.19 : 1 : 3
18 : 21 : 1 : 3
empirical formula = C₁₈H₂₁NO₃
It is codeine .
Answer:
1.2 cm³.
Explanation:
The following data were obtained from the question:
Mass of neckl = 40 g
Density of gold = 19.3 g/cm³
Volume of gold =..?
Next, we shall determine the mass of the gold in the necklace.
From the question given above, we were told that 58% of the mass of the necklace is gold. Thus, we can obtain the mass of the gold in the necklace as follow:
Mass of neckl = 40 g
Mass of gold =?
Mass of gold = 58% × 40
Mass of gold = 58/100 × 40
Mass of gold = 23.2 g
Therefore, the mass of the gold in the necklace is 23.2 g
Finally, we shall determine the volume of the gold in the necklace as follow:
Density of gold = 19.3 g/cm³
Mass of gold = 23.2 g
Volume of gold =..?
Density = mass /volume
19.3 = 23.2/Volume
Cross multiply
19.3 × Volume = 23.2
Divide both side by 19.3
Volume = 23.2 / 19.3
Volume of gold = 1.2 cm³
Therefore, the volume of the gold in the necklace is 1.2 cm³
