Answer:
30 g
Explanation:
<em>For CaCl₂</em>
3CaCl₂ + 2Na₃PO₄ ⟶ Ca₃(PO₄)₂ + 6NaCl
Moles of CaCl₂ = <em>c</em>×<em>V</em> = 5.0 × 10⁻² × 2.0 = 0.100 mol
Moles of Na₃PO₄ = 0.100 × 2/3 = 0.0667 mol
Mass of Na₃PO₄ = 0.0667 × 163.94 = 10.9 g
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<em>For Mg(NO₃)₂
</em>
3Mg(NO₃)₂ + 2Na₃PO₄ ⟶ Mg₃(PO₄)₂ + 6NaCl
Moles of Mg(NO₃)₃ = <em>c</em>×<em>V</em> = 8.5 × 10⁻² × 2.0 = 0.170 mol
Moles of Na₃PO₄ = 0.170 × 2/3 = 0.113 mol
Mass of Na₃PO₄ = 0.113 × 163.94 = 1 g
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Total mass of Na₃PO₄ = 10.9 + 18.6 = 29.5 g
To two significant figures, mass = 30 g
The best way to separate out a precipitate is using vacuum filtration. Use water to rinse out the flask thoroughly and wash the precipitate, followed by a quick rinse with ethanol to help dry it. After a few minutes on the vacuum pump, the precipitate should be ready to scrape off.<span> Also, centrifugation can be an option for small amounts especially if you just need the filtrate. For reasonable amounts, a Millipore setup or Gooch type crucible works nicely for quantitative analysis.</span>
Nuetrons=neutral
protons =positive
electrons=negative
The less buoyant oceanic plate sinks and slides under the continental plate
