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maw [93]
3 years ago
9

The mass of a toy spoon is 7.5 grams, and its volume is 3.2 ml. What is the density of the toy spoon?

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
8 0

Answer:

<h2>The answer is 2.34 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 7.5 g

volume = 3.2 mL

The density is

density =  \frac{7.5}{3.2}  \\  = 2.34375

We have the final answer as

<h3>2.34 g/mL</h3>

Hope this helps you

Anon25 [30]3 years ago
7 0

10.7 because i said sdfghj

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Given only the following data, what can be said about the following reaction?3H2(g) + N2(g)---&gt; 2NH3(g) ΔH=-92kJA.) The entha
emmainna [20.7K]

Answer:

D.) Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.

Explanation:

For the reaction:

3H₂(g) + N₂(g) → 2NH₃(g)

The enthalpy change is ΔH = -92kJ

This enthalpy change is defined as the enthalpy of products - the enthalpy of reactants. As the enthalpy is <0, The enthalpy of products is <em>lower </em>than the enthalpy of reactants.

Also, it is possible to obtain the enthalpy change from the bond energies of products - bond energies of reactants, thus, The total bond energies of products are <em>lower</em> than the total bond energies of reactants.

The rate of the reaction couldn't be determined using ΔH.

As the bond energy of ammonia is lower than bonds of nitrogen and hydrogen, <em>D. Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.</em>

I hope it helps!

3 0
3 years ago
1.) Calculation: If 9.02 x 1024 particles of vinegar (HC2H3O2)HC2H3O2) are added to 16.5 moles of eggshell (CaCO3) and 6.35 mole
blsea [12.9K]

The theoretical yield of acetate is 2607 g. The actual yield of acetate is 1066.8 g. The percentage yield of acetate is 41%.

If 1 mole of vinegar contains 6.02  x 10^23 particles

x moles of vinegar contains 9.02 x 10^24 particles

x = 1 mole x 9.02 x 10^24 /6.02 x 10^23

x = 15 moles of vinegar

The reaction is as follows;

2HC2H3O2 + CaCO3 -----> Ca(C2H3O2)2 + H2O + CO2

Since 2 moles of vinegar reacts with 1 mole of carbonate

x moles of vinegar reacts with 16.5 moles of carbonate

x =  2 moles x 16.5 moles/ 1 mole

x = 33 moles of vinegar

We can see that the vinegar is the reactant in excess hence the carbonate is the limiting reactant.

Theoretical yield = 16.5 moles x 158 g/mol = 2607 g

Actual yield = 6.35 moles  x 158 g/mol = 1066.8 g

Percent yield = 1066.8 g/2607 g × 100/1

= 41%

Learn more: brainly.com/question/13440572?

7 0
3 years ago
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