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mel-nik [20]
3 years ago
15

Which of the statements below is true for the following set of numbers?

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

The range is 40 and the midrange is 20.

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Can someone help me with #s 16 18 19 20 I WILL GIVE BRAINLIEST
Masteriza [31]

Answers & Step-by-step explanation:

<h2>PEMDAS (Parenthesis, exponents, multiplication, division, addition, subtraction)</h2>

Now let's solve your problems!

<h2>___________________________________________________</h2><h2>16.</h2>

First, we see if there are any parentheses. Since there are no parentheses, we will evaluate the exponent 3² first.

After this, our problem now looks like this:

<h2>\frac{41 - 9}{6 * 3 -26}</h2>

Next, since multiplication (not subtraction) is next on the list, we will evaluate 6 × 3, which equals 18.

After that, we will subtract:

41 - 9 = 32

18 - 26 = -8

We now have 32/-8 or 4/-1 or simply -4.

<h2>The answer is: -4</h2><h2>___________________________________________________</h2><h2>17.</h2>

With this, one, note the parentheses. This means that we will do these operations first.

(21 - 4²) = 5

(3 + 1) = 4

The problem now looks like this:

\frac{5 * 4}{8^{2}-44}

Next, we do the exponents:

8² = 64

After that, we do the multiplication of 5 x 4, which equals 20.

We now have 20/64 - 44, which simplifies to 20/20 or 1/1 or 1.

<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2>18.</h2>

Again, we see parentheses, so that means we need to do these operations first.

(6² - 20) = 16

We now have:

48 ÷ 16 + 5

48/16 = 3 and 3 + 5 = 8

<h2>The answer is: 8</h2><h2>___________________________________________________</h2><h2>19.</h2>

Here, we see an exponent 3³, so we'll need to evaluate this first.

3³ = 27

We now have:

4 × 27 ÷ 18 + 14

4 × 27 = 108

108/18 = 6

And finally:

6 + 14 = 20

<h2>The answer is: 20</h2><h2>___________________________________________________</h2><h2>20.</h2>

Here we again see the parentheses, which means we need to evaluate the subtraction first.

3 - 8 = -5

We now have:

11 + 2 (-5)

2 × -5 = -10

11 + -10 (same as 11 - 10) = 1

<h2>The answer is: 1</h2><h2>___________________________________________________</h2><h2><em>I AM ALWAYS HAPPY TO HELP :)</em></h2>
7 0
3 years ago
James earned $39,600 last year. He paid $11,250 towards rent and $1,422 in car payments. What percent of his earnings did Jon pa
tester [92]
Step 1:
Add rent & car payments

=11,250+1422
=$12,672

Step 2:
to determine %, set up a proportion
12,672 is to his total of 39,600 as x is to 100

12,672/39,600 = x/100
cross multiply
(12,672)(100) = (39,600)(x)
1,267,200= 39,600x
divide both sides by 39,600
32%= x

OR

Alternative Step 2:
12,672 ÷ 39,600= 0.32
Alternative Step 3:
0.32 x 100 = 32%
or move decimal to the right 2 places

His rent and car payments are 32% of his earnings.

Hope this helps! :)
5 0
3 years ago
Read 2 more answers
Describe how you could use algebraic operations to solve the equation 1 = -3x + 4
Anna11 [10]

Answer:

x=1

Step-by-step explanation:

3x=4-1

3x=3

x=1

3 0
3 years ago
14 less than the quotient of 63 and a number h
Monica [59]
<span>quotient of 63 and a number h would be 63/h
14 less than that would be 63 over h - 14

</span>
6 0
3 years ago
Read 2 more answers
A cylinder with a radius of 12cm and a height of 20cm has the same volume as a cone with a radius of 8cm. What is the height of
ivanzaharov [21]

Answer: 135cm

Step-by-step explanation

Volume of a cylinder = πr²h

Volume of a cone. = 1/3πr²h

The two shapes are both solid shapes.

Since the have same volume, we can then equate the two together and solve for the height of the cone.

Now make H the height and R the radius of the cylinder and h the height and r the radius of the cylinder.

Now equating the two

πR²H = 1/3πr²h

Now substitute for the values now

Multiply through by 3

3πR²H = πr²h

But π is common so it could be obliterated from the equation

3R²H = r²h

3 x 12² x 20 = 8² x h

3 x 144 x 20 = 64 x h

60 x 144 = 64h

8640. = 64h

Therefore

h = 8640/64

= 135cm

8 0
3 years ago
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