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castortr0y [4]
2 years ago
9

F 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7

Mathematics
1 answer:
Ivenika [448]2 years ago
6 0
While lottta number
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What (3×5^2)/(5)^2 equal? Plz answer fast and with work and I will give brainliest
balu736 [363]

Answer:

The answer is 3.

Step-by-step explanation:

Given that the Indices Law is,

{a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

{a}^{0}  = 1

So the expression is :

3 \times  {5}^{2}  \div  {5}^{2}

= 3 \times  {5}^{2 - 2}

= 3 \times  {5}^{0}

= 3 \times 1

= 3

4 0
3 years ago
A sphere of radius 3 is inscribed in a cylinder. What is the volume inside the cylinder but not inside the sphere?
Fed [463]

Answer:

18pi units³ or 56.5 units³ (3 sf)

Step-by-step explanation:

pi×r²×h - (4/3)(pi×r³)

r = 3 h = 2r = 6

pi(3²×6 - (4/3)(3³))

18pi units³

8 0
3 years ago
Find the value of x. Then tell whether the side lengths from a Pythagorean triple sides 20,16 find x
Tema [17]

Answer:

x = 12

Step-by-step explanation:

Pythagorean triplet

12,16,20

So, the value of x is 12

x + 256 = 400

x = 400 - 256

x = 144

The square of 12 is 144

6 0
2 years ago
I need help! please<br> domain range and end behavior of f(x)=1-x^2
Reptile [31]

Answer:

Here's a screenshot. Hope this helps

8 0
3 years ago
Read 2 more answers
Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?
sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y  and  RT ≅ WY.

we are given the following assumptions:

∠W = x + 5  

∠X = 3x - 9


∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

A)

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

B)

if ∠R = 2x + 20 then as  ∠W≅∠R

⇒  x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

C)

if ∠S=2x^2+5 then as  ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

D)

if ∠R =  2x

^2

+ 5 then as ∠W≅∠R.

⇒ x+5=

2x

^2

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not  possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal  to 180°

Hence, option D is not possible.

Hence, option A is correct.



4 0
3 years ago
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