Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Answer:
3x
Step-by-step explanation:
I believe the answer is 75 I am not sure but I adds up because 4*.75 equals to 3 there is another way to solve this though we can do the is over of equals % over 100 then we still get three have a nice day and good luck on your assignment (:
The correct answer is C) t₁ = 375,

.
From the general form,

, we must work backward to find t₁.
The general form is derived from the explicit form, which is

. We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

Using the products of exponents, we can "split up" the exponent:

We know that 5⁻¹ = 1/5, so this gives us

Comparing this to our general form, we see that

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375
The recursive formula for a geometric sequence is given by

, while we must state what t₁ is; this gives us