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navik [9.2K]
3 years ago
10

Determine if the two triangles are congruent. If they are, state how you know.

Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

B) SAS

Step-by-step explanation:

The angles between the two known equal sides are called a vertical angle and are equal. Thus you know Side-Angle-Side proves congruency.

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Grant is a member of a book club. He pays a $10 yearly membership fee and can purchase books through the club for $2.75 each. Hi
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$45.75 because you take the 2.75 and times it by how may books which is 13 and you get $35.75 then you add your $10 and it will give you $45.75
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3. Can a triangle have sides with the given lengths?<br> 8 cm, 7 cm, 9 cm
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Answer:yes

Step-by-step explanation:

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A store is instructed by corporate headquarters to put a markup of 25​% on all items. An item costing ​$24 is displayed by the s
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Answer: The correct selling price is $29.97.

Step-by-step explanation:

Since we have given that

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So, Amount of mark up would be

So, Amount after mark up would be

Hence, the correct selling price is $29.97.

The manager's likely error is that he has put the selling price the mark up amount only i.e $2.9≈$3 instead of adding the mark up amount to the cost price.

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3 years ago
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An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude
AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

p\pm z*\sqrt{\frac{p*(1-p)}{n} }

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students

60 students were in the sample.

8 0
3 years ago
Find the area of the shaded region.
taurus [48]

Answer:

426.96 \:  {km}^{2}

Step-by-step explanation:

Area of the shaded region = Area of triangle with base 40 km and height 27 km - Area of circle with radius (12/2) 6 km.

=  \frac{1}{2}  \times 40 \times 27  - 3.14 \times  {(6)}^{2}  \\  \\  = 20 \times 27 - 3.14 \times 36 \\  \\  = 540 - 113.04 \\ \\   = 426.96 \:  {km}^{2}

5 0
3 years ago
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