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vichka [17]
3 years ago
5

Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312k

m apart after 4 hours. Find the speed of each car.​
Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

Speed of car B is 33 km/h and speed of car A is 45\,\,km/h

Step-by-step explanation:

Let speed of car B be x km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = (12+x) km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = 4(12+x) km = (48+4x) km

Distance travelled by car B in 4 hours = 4x km

Also, cars A and B are 312km apart after 4 hours.

48+4x+4x=312\\48+8x=312\\8x=264\\\\x=\frac{264}{8}\\\\x=33\,\,km/h

Speed of car B is 33 km/h and speed of car A is 12+x=12+33=45\,\,km/h

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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
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Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

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