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vichka [17]
2 years ago
5

Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312k

m apart after 4 hours. Find the speed of each car.​
Mathematics
1 answer:
Zina [86]2 years ago
5 0

Answer:

Speed of car B is 33 km/h and speed of car A is 45\,\,km/h

Step-by-step explanation:

Let speed of car B be x km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = (12+x) km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = 4(12+x) km = (48+4x) km

Distance travelled by car B in 4 hours = 4x km

Also, cars A and B are 312km apart after 4 hours.

48+4x+4x=312\\48+8x=312\\8x=264\\\\x=\frac{264}{8}\\\\x=33\,\,km/h

Speed of car B is 33 km/h and speed of car A is 12+x=12+33=45\,\,km/h

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8 0
2 years ago
For the function, evaluate the given expression. f(x, y) = 139 − x2 − y2. Find f(3, −9).
elena55 [62]

The value of the expression f(x,y)=139-x^{2} -y^{2} at (3,-9) is 49.

Given that the expression is  f(x,y)=139-x^{2} -y^{2} and point (3,-9).

We are required to find the value of the expression f(x,y)=139-x^{2} -y^{2} at (3,-9).

Expression is basically a combination of numbers, fractions, symbols, coefficients,determinants,indeterminants. They are mostly not found in equal to form.

Expression is f(x,y)=139-x^{2} -y^{2}.

To find the value of expression f(x,y) at (3,-9).

f(3,-9)=139-(3)^{2} -(9)^{2} (Squaring 3 and -9)

f(3,-9)=139-9-81   (Now add 9 and 81 and put minus sign before the result)

f(3,-9)=139-90    

f(3,-9)=49            (Now subtract 90 from 139)

Hence the value of the expression f(x,y)=139-x^{2} -y^{2} at (3,-9) is 49.

Learn more about expressions at brainly.com/question/723406

#SPJ4

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