Sine angle A = 2.2 / 2.6
sine angle A =
<span>
<span>
<span>
0.8461538462
</span>
</span>
</span>
angle A = arc sine (<span>0.8461538462)
</span>angle A = 57.796 Degrees
cosine angle B = 2.2 / 2.6
cosine angle B = <span>0.8461538462
</span>angle B = arc sine (<span>0.8461538462)
</span>angle B = 32.204 Degrees
AC^2 = 2.6^2 - 2.2^2
AC^2 =
<span>
<span>
<span>
6.76
</span>
</span>
</span>
-4.84
AC^2 =
<span>
1.92
</span>AC =
<span>
<span>
<span>
1.3856406461
</span>
</span>
</span>
Answer:
x^2(4+x)
Step-by-step explanation:
you have to factor out x^2 off both equations since that's the only thing that you can divide off the equations
Well 5 - 11 is -6 so there is your anser
Answer:
so x = 5 is not true statement
Step-by-step explanation:
well to prove x = 5 you need to get get alone or solve for x
3x = 10-5 --> 3x = 5
now you need to get x alone do this by dividing 3 by both sides
3x = 5 --> x = 5/3
x = 1.6
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
