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inessss [21]
3 years ago
5

Three-fourths of the voters supported the bond measure. If there were

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

6000

Step-by-step explanation:

Divide top and bottom by the common factor.  

\dfrac{3 }{4}  \times 8000 = 3 \times 2000

Simplify

3 × 2000 = 6000

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Find the mean 1,10,7,6,4,8 absolute devation
madreJ [45]

Answer:

6

Step-by-step explanation:

can i get u kno wah

8 0
3 years ago
The delivery ramp at the corner cafe id a right triangle. The hypotenuse is 4 meters long. One leg is 3 meters long. What is the
disa [49]

Answer:

f. sqrt 7 meters

Step-by-step explanation:

we use Pythagoras' theorem here,

let the unknown side be x,

therefore,

=> 3² + x² = 4²

=> x² = 16 - 9

=> x = √7 m

7 0
3 years ago
Read 2 more answers
Write the equation in exponential form. Assume that all constants are positive and not equal to 1.
algol13

Answer:

1.     16 = 4^2

2.    2 = {16}^{\frac{1}{4}}

3.    log_2 y=z

Step-by-step explanation:

1.\ log_2 16=4

Write in exponential form

Using the law of logarithm which says if

log_b A=x

then

A = b^x

By comparison;

A = 16; b = 2 and x = 4

The expression log_2 16=4 becomes

16 = 4^2

2.\ log_{16} 2=\frac{1}{4}

Write in exponential form

Applying the same law as used in (1) above;

A = 2; b = 16 and x = \frac{1}{4}

The expression log_{16} 2=\frac{1}{4} becomes

2 = {16}^{\frac{1}{4}}

3.\ 2^z=y

Write in logarithm form

Using the law of logarithm which says if

b^x =A

then

log_b A=x

By comparison;

b = 2; x = z and A = y

The expression 2^z=y becomes

log_2 y=z

3 0
3 years ago
The daily mean temperature in a particular place is 83. how many cooling-degree days were accumulated?
olga55 [171]
Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating. 
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
X=18
4 0
3 years ago
(b-c)3 +(c-d) raise to3 3+(d-b)3
Juliette [100K]

Answer:3 b − 2 c− d , t o 3 , 3 + 3d − 3 b

Step-by-step explanation:

( b − c ) ⋅ 3 + ( c -d )  raise  t o  3   3 + ( d − b ) ⋅ 3

Write the problem as a mathematical expression.

( b − c ) ⋅ 3 +( c − d )  raise  t o3   3+ ( d − b) ⋅ 3

Remove parentheses.

( b − c) ⋅ 3 + c − d , t o 3 , 3 + ( d − b ) ⋅ 3

Simplify each term.

Apply the distributive property.

b ⋅ 3 − c ⋅ 3 + c− d

Move  3  to the left of  b . 3 ⋅ b − c ⋅ 3 + c − d

Multiply  3  by  − 1  ⋅ 3 b − 3 c + c − d

Add  − 3 c  and  c. 3 b − 2 c − d , t o 3 , 3 + ( d − b ) ⋅ 3

Simplify each term.

Apply the distributive property.

3 + d  ⋅ 3 − b  ⋅ 3

Move  3  to the left of  d . 3 + 3 ⋅ d − b ⋅ 3

Multiply  3  by  − 1 . 3 + 3 d − 3 b

4 0
3 years ago
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