1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nevsk [136]
3 years ago
10

A customer buys bouquets of tulips and bouquets of roses for $.. What is the price of a bouquet of roses?

Mathematics
1 answer:
olchik [2.2K]3 years ago
7 0

Question:

A customer buys bouquets of tulips and bouquets of roses for $40.25. The bouquet contained 17 tulips and cost $18.25. What is the price of a bouquet of roses?

Answer:

Rose =\$22.00

Step-by-step explanation:

Given

Total = \$40.25

Tulips = \$18.25

Required

The cost of a bouquet of roses

Since the customer bought a bouquet each, the formula to use is:

Total = Tulip + Rose

Make Rose the subject

Rose =Total - Tulip

Rose =\$40.25 - \$18.25

Rose =\$22.00

<em>A bouquet of rose costs $22.00</em>

You might be interested in
Jaz was 43 inches tall. Eighteen months later, she was 52 inches tall. The constant rate of change for Jaz's height was .
maxonik [38]

Answer:

Constant rate of change for Jaz height will be 0.5 inch per month

Step-by-step explanation:

Jaz present height is 43 inches.

Eighteen months later her height will be 52 inches.

Now we know rate of change will be represented by the formula

Rate of change of height =

=

= 0.5 inch per month

The constant rate of change for Jaz height will be 0.5 inch per month.

Read more on Brainly.com - brainly.com/question/2012372#readmore

7 0
3 years ago
A line passes through the points (3,14) and (7,18) Write a linear function rule in terms of x and y for this line, Help! I might
MrRissso [65]

Answer:

y=1x+11

Step-by-step explanation:

1. Find the slope of the given points

\frac{y2-y1}{x2-x1}

\frac{18-14}{7-3} =\frac{4}{4} =1

2. Pick any point to find the y-intercept

(3, 14)

x=3, y=14, m=1

3. Substitute

y=mx+b

14=1(3)+b

14=3+b

14-3=b

11=b

4. Write the linear function rule

y=mx+b

y=1x+11

3 0
2 years ago
Read 2 more answers
24 students and Jamal's class are wearing tennis shoes there are 30 students in this class your mom says that 70% of this class
mel-nik [20]
Im not sure if i am understanding the question correctly... 

If you are asking if Jama's mom is correct, then no. she is wrong. this is because 

if you take the proportion,  (is/of)=(%/100) you get (x/30)=(70/100). You then solve for x which in this case would be 21 students are wearing tennis shoes.

Hope this helps. 
3 0
3 years ago
Which of these is a correct expansion of (3x -2)(2x^2+5)
labwork [276]

(3x−2)(2x^2+5)

=(3x+−2)(2x^2+5)

=(3x)(2x^2)+(3x)(5)+(−2)(2x^2)+(−2)(5)

=6x^3+15x−4x^2−10

=6x^3−4x^2+15x−10

4 0
4 years ago
Read 2 more answers
Solve 8[7 - (6x -6)] + 6x =0.
Rus_ich [418]
Solve for x:8 (13 - 6 x) + 6 x = 0
8 (13 - 6 x) = 104 - 48 x:
6 x + 104 - 48 x = 0
6 x - 48 x = -42 x:
-42 x + 104 = 0
Subtract 104 from both sides:
(104 - 104) - 42 x = -104
104 - 104 = 0:
-42 x = -104
Divide both sides of -42 x = -104 by -42:
(-42 x)/(-42) = -104/(-42)
(-42)/(-42) = 1:
x = -104/(-42)
The gcd of 104 and -42 is 2, so -104/(-42) = -(2×52)/(2 (-21)) = 2/2×(-52)/(-21) = (-52)/(-21):
x = (-52)/-21
Multiply numerator and denominator of (-52)/(-21) by -1:
Answer:  x = 52/21
8 0
3 years ago
Other questions:
  • Help me please.
    8·1 answer
  • I need help on this problem please help me.
    11·1 answer
  • Mark traveled 455 miles in 5 hours. At this rate how far could he travel in 7 1/2 hours
    9·1 answer
  • What's the answer too the problem
    14·1 answer
  • Help Please question in the picture
    5·1 answer
  • Solve q=w-4/ z for w
    11·1 answer
  • What is the slope of the line
    5·1 answer
  • Help please!!!!!!!!!!
    11·1 answer
  • How to find polynomial expressions
    5·1 answer
  • Which is the graph of the system x + 3y &gt;-3 and y &lt; 1x+1?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!