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Snezhnost [94]
3 years ago
14

Five more than three-fourths a number is -19

Mathematics
1 answer:
gogolik [260]3 years ago
3 0

Answer:

5 + 3/4x = -19

Step-by-step explanation:

more than means adding

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Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change. The sandwich cost $7.75 and sales tax was $
EleoNora [17]

Given

Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.

The sandwich cost $7.75 and sales tax was $0.47.

Find out the  cost of her drink

To proof

Let the cost of her drink be x.

As given in the question

Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.

Elysse paid for her sandwich and drink = 10 - 0.63              

                                                                 =  $ 9.37

sandwich cost $7.75 and sales tax was $0.47

Than the equation becomes

x = 9.37 - (7.75 + 0.47)

x = 9.37 - 8.22

x = $ 1.15

The cost of the drink is $ 1.15.

Hence proved      

4 0
3 years ago
Read 2 more answers
Kenny reads 5/8 page in 2/3 minute. <br> How many inches did it snow per hour?
Morgarella [4.7K]
It would be 15/16. hope that helps.
5 0
4 years ago
When exchanging US Dollars (USD) for Philippine Peso (PHP) the number of Philippine Pesos
MAXImum [283]

Answer:

  • k = 35.576
  • 24,903.20 PHP

Step-by-step explanation:

We want k such that ...

  PHP = k·USD

Then the value of k is ...

  PHP/USD = k = 12,451.60/350

  k = 35.576

__

700 USD will convert to twice as much as 350 USD, so ...

  700 USD = 700·35.576 PHP = 24,903.20 PHP

3 0
3 years ago
Combine like terms. What is a simpler form of the expression?<br><br> -3(-4y + 3) + 7y<br><br> Solve
Umnica [9.8K]
 distribute the -3 to the -4y and the 3 making the question 12y-9+7y then add common factors to get 19y-9
4 0
3 years ago
Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half
BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0
4 years ago
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