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3 years ago

Match each proportion to its solution.

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

x/10=-30/100 : -3

5/35 = 1/a : 7

2/x = 100/15 : .3

12/k = 4/1 : 3

2/8 = g/4 : 1

Step-by-step explanation:

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Three vertices of parallelogram WXYZ are X(–2,–3), Y(0, 5), and Z(7, 7). Find the coordinates of vertex W

Serhud [2]

The coordinates of the vertex W are (5 , -1)

Step-by-step explanation:

In the parallelogram, the diagonal bisect each other

To find a missing vertex in a parallelogram do that:

Find the mid-point of a diagonal whose endpoints are given
Use this mid-point to find the missing vertex
The mid point rule is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

∵ WXYZ is a parallelogram

∴ Its diagonals are WY and XZ

∵ The diagonal bisect each other

- That mean they have the same mid-point

∴ They intersect each other at their mid-point

∵ x = (-2 , -3) and z = (7 , 7)

∴ $x_{1}$ = -2 and $x_{2}$ = 7

∴ $y_{1}$ = -3 and $y_{2}$ = 7

- Substitute them in the rule of the mid point to find the

mid-point of XZ

∴ $M_{XZ}=(\frac{-2+7}{2},\frac{-3+7}{2})=(2.5 , 2)$

∴ The mid-point of diagonals WY and XZ is (2.5 , 2)

Let us use it to find the coordinates of vertex W

∵ W = (x , y) and Y = (0 , 5)

∴ $x_{1}$ = x and $x_{2}$ = 0

∴ $y_{1}$ = y and $y_{2}$ = 5

- Equate 2.5 by the rule of the x-coordinate of the mid-point

∵ $2.5=\frac{x+0}{2}$

- Multiply both sides by 2

∴ 5 = x + 0

∴ 5 = x

∴ The x-coordinate of point W is 5

- Equate 2 by the rule of the y-coordinate of the mid-point

∵ $2=\frac{y+5}{2}$

- Multiply both sides by 2

∴ 4 = y + 5

- Subtract 5 from both sides

∴ -1 = y

∴ The y-coordinate of point W is -1

The coordinates of the vertex W are (5 , -1)

Learn more:

You can learn more about the mid-point in brainly.com/question/10480770

#LearnwithBrainly

4 0

3 years ago

2p-1<br>make p the subject

jok3333 [9.3K]

Answer:

2p-1/p

Step-by-step explanation:

7 0

3 years ago

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Right triangle LMN has vertices L(7, –3), M(7, –8), and

prohojiy [21]

We are given the vertices of the triangle with their respective coordinates. For the vertex L, the translated coordinates is also given. So, from the original coordinates of L and the new coordinates, we can get the rule used during translation:(7, -3) -> (7 + a, -3 + b) = (-1, 8)7 + a = -1a = -8
-3 + b = 8b = 11
Therefore, the answer is:(x, y) → (x – 8, y + 11)

6 0

3 years ago

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0

2 years ago

Why is circle 1 similar to circle 2

Kobotan [32]

Your answer is letter A.

Hope this helps :)

8 0

3 years ago

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