Answer:
y=-1/3x+1
Step-by-step explanation:
The slope of this line is negative, and is equal to rise over run.
To find slope, count the number of spaces it has moved down or up, and then the number of spaces it has moved left or right.
The y intercept is represented by +1, and is where the line crosses the y axis.
Hope this helps!
Answer:
36years
Step-by-step explanation:
Let charity present age be x
Charity daughter present age be y
Charity husband present age be z
If the sum of their ages ten years to come is 117, then;
10+x+10+y+10+z = 117
30+x+y+z = 117
x+y+z = 87 ... 1
If charity is four times as old as her daughter, then;
x = 4y
y = x/4 ... 2
If she is also six years younger than her husband, then;
x = z- 6
z = x+6 .. 3
Substitute 2 and 3 into 1;
x + x/4 + (x+6) = 87
Multiply through by 4
4x + x + 4(x+6) = 4(87)
5x+4x+24 = 348
9x = 348 - 24
9x = 324
x = 324/9
x = 36
hence Charity is 36years old today
• The value of the discriminant ,D= -16
,
• The solution to the quadratic equation is

Step - by - Step Explanation
What to find?
• The discriminant d= b² - 4ac
,
• The solution to the quadratic equation.
Given:
5x² - 2x + 1=0
Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0
a=5 b=-2 and c=1
Uisng the quadratic formula to solve;
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
The discriminant D=b² - 4ac
Substitute the values into the discriminant formula and simplify.
D = (-2)² - 4(5)(1)
D = 4 - 20
D = -16
We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;
![x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-2%29%5Cpm%5Csqrt%5B%5D%7B-16%7D%7D%7B2%285%29%7D)
Note that:
√-1 = i
![x=\frac{2\pm\sqrt[]{16\times-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%5Ctimes-1%7D%7D%7B10%7D)
![x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%7D%5Ctimes%5Csqrt%5B%5D%7B-1%7D%7D%7B10%7D)




That is;
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)