At STP, it is at 273 K and 1.00 atm.
Use PV=nRT to and solve for n (number of mol of N2)
1.00 atm • 4.40L / 0.08206 Latm/molK • 273 K = 0.196 mol N2
There are two mol of N2 for every two mol of NH4NO2 (the number of mol of both are equal)
Find the molar mass of NH4NO2 = 64.1 g
Multiply the number of mol by the molar mass
0.196 mol • 64.1 = 12.6 g NH4NO2
Answer: Option (3) is the correct answer.
Explanation:
Atomic number of nitrogen is 7 and its electronic configuration is
. Thus, we can see that valency of nitrogen is 5.
So, one nitrogen atom has one lone pair of electron.
Therefore, when two nitrogen atoms will bond together then there will be three pairs of electrons bonded together and one lone pair of electron on each nitrogen atom.