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AveGali [126]
3 years ago
5

What physical properties does radium have

Chemistry
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

Radium is silvery, lustrous, soft, intensely radioactive. It readily oxidizes on exposure to air, turning from almost pure white to black. Radium is luminescent, corrodes in water to form radium hydroxide. Although is the heaviest member of the alkaline-earth group it is the most volatile..

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What is the hybridised structure of B2H6?
Sonja [21]
<em>it is given  as as under: :

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6 0
3 years ago
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How did oxygen come up to make 21% of the earth's present atmosphere?
MakcuM [25]
Tiny organisms known as cyanobacteria, or blue-green algae.
4 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 56.0 at 278 K. 2CH2Cl2(g) CH4(g) + CCl4(g) When a sufficiently large
BabaBlast [244]

Answer:

  • <u>21.5 M</u>

Explanation:

<u>1) Equilibrium equation (given):</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

<u>2) Write the concentration changes when some concentration, A, of CH₂Cl₂ (g) sample is introduced into an evacuated (empty) vessel:</u>

  • 2CH₂Cl₂ (g) ⇄ CH₄ (g) + CCl₄ (g)

           A - x                 x              x

<u>3) Replace x with the known (found) equilibrium concentraion of CCl₄ (g) of 0.348 M</u>

  • 2CH₂Cl₂ (g)   ⇄ CH₄ (g) + CCl₄ (g)

          A - 0.3485       0.348       0.348

<u>4) Write the equilibrium constant equation, replace the known values and solve for the unknown (A):</u>

  • Kc = [ CH₄ (g) ] [ CCl₄ (g) ] / [ CH₂Cl₂ (g) ]²

  • 56.0 = 0.348² / A²

  • A² = 56.0 / 0.348² = 462.

  • A = 21.5 M ← answer

7 0
3 years ago
Explain why it is necessary to balance chemical equations in terms of maintaining equilibrium. How can you tell when a chemical
LUCKY_DIMON [66]

Answer:

See explanation.

Explanation:

Hello,

In this case, we say that chemical reactions are governed by the law of conservation of mass, which states that matter cannot be neither created nor destroyed by transformed, for that reason, we need to balance chemical reactions in order to ensure all the atoms to be in the same quantity at both reactants and products.

Moreover, equilibrium is defined as such condition at which the concentration of both reactants and products stop changing over the time so they become constant as well as their null reaction rate.

A widely acknowledged reaction is the HABER one which consists on the synthesis of ammonia by using elemental nitrogen and hydrogen:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

In such reaction, we have two nitrogens at both reatants and products and six hydrogens at at both reatants and products for us to obey the law of conservation of mass. Furthermore, as the time goes by, nitrogen reacts with hydrogen, nonetheless, they do not react indefinitely, they have a limit that is equilibrium, so their moles stop being consumed and remain unchanged as well as the produced moles of ammonia.

Best regards.

7 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
2 years ago
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