Question

Samuel found the difference of the polynomials. (15x^2+11y^2+8x)-(7x^2+5y^2+2x)= blankx^2+6y^2+6x What value is missing from his solution?

Answer 1

Answer:

Co-efficient of $x^{2}$ is missing.

It should be 8$x^{2}$.

Step-by-step explanation:

Given two polynomials:

1st polynomial: $15x^2+11y^2+8x$

2nd polynomial: $-7x^2+5y^2+2x$

To find:

The value in the blank:

$(15x^2+11y^2+8x)-(7x^2+5y^2+2x)= \_\_ \ x^2+6y^2+6x$

Solution:

Here, we have 3 pair of like terms.

2 terms with $x^{2}$, 2 terms with $y^{2}$and 2 terms with $x$.

Like terms can be subtracted.

Subtracting the terms with $y^{2}$, the coefficients will get subtracted.

$11y^2 - 5y^2 = 6y^2$

Subtracting the terms with $x$, the coefficients will get subtracted.

$8x -2x=6x$

Subtracting the terms with $x^{2}$, the coefficients will get subtracted.

$15x^2 - 7x^2 =\bold{8}x^2$

Therefore, the answer is:

Co-efficient of $x^{2}$ is missing.

It should be 8$x^{2}$.