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Law Incorporation [45]
3 years ago
11

I NEED THE ANSWER TO THIS NOW

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

i think the answer is the 3rd one

plz give me brainliest

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On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0.25, negative 6), and goes throug
serg [7]

The statements true about the the function f(x) = 2x2 – x – 6 are-

  • The vertex of the function is (one-quarter, negative 6 and one-eighth).
  • The function has two x-intercepts.

<h3>What is vertex of parabola?</h3>

The vertex of parabola is the point at the intersection of parabola and its line of symmetry.

Now the given function is,

f(x) = 2x^2 – x – 6

Also, it is given that the vertex is located at (0.25, -6)  and the parabola opens up, the function has two x-intercepts.

Comparing the given function with standard form,

f(x) = a x^2 bx + c

By comprison we get,

a = 2

b = -1

c = -6

Now, x-coordinate of vertex is given as,

x = -b/2a

put the values we get,

x = -(-1)/2*2

or, x = 1/4

Put the value of x in given function, so y-coordinate of the vertex is given as,

f(1/4) = 2(1/4)² - 1/4 - 6

        = -49/6

       = -6 1/8

Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-

  • The vertex of the function is (one-quarter, negative 6 and one-eighth).
  • The function has two x-intercepts.

More about vertex :

brainly.com/question/86393

#SPJ1

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1 year ago
Which set of rectangular coordinates describes the same location as the polar coordinates (4,pi)?
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\bf (\stackrel{r}{4}~,~\stackrel{\theta }{\pi })\qquad \begin{cases} x=&rcos(\theta )\\ &4cos(\pi )\\ &4(-1)\\ &-4\\ y= &rsin(\theta )\\ &4sin(\pi )\\ &4(0)\\ &0\\ \end{cases}\qquad \implies (\stackrel{x}{-4}~,~\stackrel{y}{0})

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Seven less than twice a number is no more than 77
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No because 77 is greater than the lowest number
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4w+2=2w+7<br><br> Please quick I dont have time!
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That’s the answer for this problem

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