All categories

3 years ago

the fastest elevators in the Burj Khalifa can travel 330 feet in just 10 seconds how far does the elevator travel in 11 seconds

Mathematics

1 answer:

larisa [96]3 years ago

8 0

Answer:

363 feet

Step-by-step explanation:

The ratio of feet traveled per second is 33. You can find this by diving the original feet given by the time given. 330 divided by 10 is 33. So now you know how many feet is traveled in only a second of time. Qith this information, you can mutliply your ratio by 11 to find the feet traveled in 11 seconds. 33 times 11 is 363. Hope this helps :))

You might be interested in

How do I solve this math problem?

Nat2105 [25]

Answer: 4x² + 4x - 2 - $\frac{3}{2x+3}$

Step-by-step explanation:

You can use either synthetic or long division. I am using synthetic division:

2x + 3 = 0 ⇒ x = $-\frac{3}{2}$

$-\frac{3}{2}$ | 4 10 4 -6

| ↓ -6 -6 3

4 4 -2 -3 ← -3 is the remainder

↓ ↓ ↓

4x² +4x -2 ← factored polynomial

3 0

3 years ago

The expression (n^14)(n^3) is equivalent to n^x What is the value of x

Andre45 [30]

Answer:

Step-by-step explanation:

add the exponents

7 0

3 years ago

Read 2 more answers

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago

The tree is tilted 14 degrees. Find the value of x

Mashutka [201]

I think it's 76 degrees

8 0

3 years ago

Read 2 more answers

When we make inferences about ONE POPULATION PROPORTION, what assumptions do we need to make? Mark all that apply. Group of answ

natita [175]

Answer:

Data is quantitative, data is categorical, data must be from a simple random sample, the data mut have normal distribution,

Step-by-step explanation:

When we make inference about one population proportion, we must ensure that the sample was taken randomly and observations follow a normal distribution. The sample size must be as large as possible with at least 10 counts of failures an 10 counts of successes. The individual observations must be independent. They must be quantified and categorized.

7 0

3 years ago