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3 years ago

Write 256as the product of prime factors HELP Me PlZ

Mathematics

2 answers:

otez555 [7]3 years ago

8 0

8 x 32 = 256. Both numbers are prime. Hope I helped:)

Andrew [12]3 years ago

4 0

The answer is a bro hope i helped

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The hypotenuse of a right triangle is 1m longer than twice one of the other two sides. The third side of the triangle is 15m. Fi

Dimas [21]

Let the length of unknown side be x

So, hypotenuse = 2x + 1

By pythagorean theorem ie , a² = b² + c²

(2x + 1)² = x² + 15²

4x² + 1 + 4x = x² + 225

3x² + 4x -224

(3x +28)(x-8)

x = -9.33 , 8

Since, length can't be negative

x = 8

∴Unknown side length = 8 m

Length of hypotenuse = 2 x 8 + 1 = 17 m

Hope it helps now.

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Nitella [24]

Answer:

Step-by-step explanation:

With what ??? no picture

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3 years ago

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At a dry cleaning store, it costs $1.79 to clean a man’s dress shirt and 6 times as much to clean a suit. Choose the answer that

aleksandrvk [35]

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You have to multiply 1.79 times 6 then add 1.79

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3 years ago

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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

3 years ago

Find the principle fourth root of -81, checking your answer by raising to the 4th power. If there are "no real roots," then type

kondaur [170]

Answer:

None

Step-by-step explanation:

There are actually 2 answers, 3 and -3. Although if you put it in a calculator, it would show "math error" or undefined. That's because the index is even (4) and the radicand is negative (-81)

4 0

3 years ago