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GuDViN [60]
4 years ago
11

Design a Boolean circuit that verifies whether a given integer 0 ≤ x < 16 is divisible by 5

Mathematics
2 answers:
Dmitry_Shevchenko [17]4 years ago
8 0

This question is incomplete, the complete question is;

Your boss asks you to design a Boolean circuit that verifies whether a given integer 0 < x < 16 is divisible by 5.

Every such number is represented in binary using four bits, say b₃b₂b₁b₀, and so your Boolean circuit will have four inputs. For instance, the number 13 is written in binary as 1101 and so to test its divisibility by 5 a user would feed the values b₀ = 1, b₁ = 0, b₂ = 1, and b₃ = 1 into the inputs of your circuit.

The Boolean circuit will have a single output, which should deliver the value 1 if the iput values represent a number that is divisible by 5 and 0 otherwise.

a) write down the truth table of the Boolean function F(b₀,b₁,b₂b₃) that implements this "divisible by 5" operation

b) construct a Boolean expression in disjunctive normal form that implements the Boolean function yo wrote down in a)

Answer:

Given that;

integer range = 0≤ x ≤ 16

within 4bits, we can represnt each number

(0,5,10,15)

a)  

Truth table for function that implements  divisible by 5

Integer    B3    B2    B1    B0     Y

0              0       0      0      0      1

1              0       0      0       1      0

2              0       0      1        0     0

3              0       0      1        1      0

4              0       1       0       0     0

5              0       1       0       1      1

6              0       1       1        0     0

7              0       1       1        1       0

8              1       0      0        0      0

9              1       0      0        1       0

10             1       0      1         0      1

11              1       0      1          1      0

12             1        1      0         0     0

13             1         1     0          1      0

14             1         1       1         0     0

15            1         1        1        1       1

b)

Boolean expression that implements the Boolean function from a)

from the truth table;

Boolean expression Y is;

Y = b⁻₃b⁻₂b⁻₁b⁻₀ / y₁   +   b⁻₃b₂b⁻₁b₀ / y₂   +   b₃b⁻₂b₁b⁻₀ / y₃   +   b₃b₂b₁b₀ / y₄

alexandr402 [8]4 years ago
6 0

Answer:

  circuit is in the second attachment

Step-by-step explanation:

Attached is a truth table for the desired circuit, where b3–b0 are the input bits, MSB–LSB. We notice that the output is true whenever b3=b1 and b2=b0. This can be written in DNF as ...

  Y=b_3'b_2'b_1'b_0'+b_3b_2'b_1b_0'+b_3'b_2b_1'b_0+b_3b_2b_1b_0

More compactly, it can be written in terms of the exclusive-nor function as ...

  y=(b_3\odot b_1)\wedge(b_2\odot b_0)

A circuit diagram showing this circuit is the second attachment. (A–D are the input bits, in order MSB–LSB (or its reverse)).

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please help me with it and dont just put random letters cause i dont know why u do it its not like u can buy a house with these
BartSMP [9]

Answer:

v=432cm

sA=144cm

Step-by-step explanation:

1)))

v=w*d*h

v=3*9*16

v=432cm

2)))

sA=h*w

sA=16*9

sA=144cm

6 0
2 years ago
Read 2 more answers
a straight line has a equation 4x + 3y = 12 . find the gradient of the line and the coordinates of the point where this line cro
Komok [63]
4x + 3y = 12
3y = -4x + 12
y = -4/3x + 4........so the slope (or gradient) is -4/3...because in y = mx + b form, the slope(gradient) is in the m position and the y int is in the b position....so if u wanted to know the y axis, it would be (0,4)

the x intercept (where the line crosses the x axis) can be found by subbing in 0 for y in the original equation or the slope intercept equation, and solving for x.
4x + 3(0) = 12
4x = 12
x = 12/4 = 3....so the x intercept is (3,0)
4 0
3 years ago
What is the solution set of |- x| = - 10?
Vaselesa [24]

Answer:

No Solution

Step-by-step explanation:

|-x| always = | x |

| x | = - 10

If x = 10, It does not equal to - 10

If x = -10, It becomes 10 because its an absolute value, So it does not equal to -10

So, there is No Solution

7 0
3 years ago
2x+y=-9<br> -3x+11=y whathe is the answer
insens350 [35]
[ 2x + y = -9 ] x -3
[- 3x +11= y ] x 2

-6x -3y = 27
-6x + 22 = 2y

-6x +27 = 3y
-6x +22 = 2y

5 = y

-6x -3x5 = 27
-6x -15 = 27
-6x = 42
-x = 42/6
-x = 7
x = -7

answer

x = -7
y = 5




8 0
3 years ago
Solve for p. 7 + 2p = p
dalvyx [7]
7 + 2p = p

subtract 2p on both sides. it now leaves you with:

7= -p

divde both sides by -1.

-7 = p
5 0
4 years ago
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