Question

There is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.

Answer 1

• Mass=2kg
• Velocity=40m/s

We know

$\boxed{\sf K.E=\dfrac{1}{2}mv^2}$

• m denotes to mass
• v denotes to velocity

$\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2$

$\\ \sf\longmapsto K.E=40^2$

$\\ \sf\longmapsto K.E=1600J$