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3 years ago

What scenario shows responsible behavior with regard to lab safety

1 answer:

5 0

You should ALWAYS wear lab coats and safety goggles because if anything gets in your eye that will be bad.You should always wear sneakers.If any chemical falls on your open toes then that can hurt you and effect you in a lot of ways.Some labs have this rule,you are not aloud to eat or drink in lab.Hope this helps!

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True or false? If an element can form covalent bonds then it will never be involved in ionic bonding.

vladimir2022 [97]

Answer:

true

Explanation:

because the bonds in that element can only be shared but not transferred , but sometimes it depends on the element

7 0

3 years ago

Read 2 more answers

Why do the waves have different speeds in different layers of Earth's surface?

Genrish500 [490]

Answer:

Material's density

Explanation:

Seismic waves travel at different rates of speed based on a material's density. Hopefully, you understand that the Earth has three main layers: the crust, mantle, and core. Earthquake waves move faster through solids.

6 0

2 years ago

An electron with a speed of 1.9 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 N acts

Nimfa-mama [501]

Explanation:

It is given that,

Speed of the electron in horizontal region, $v=1.9\times 10^7\ m/s$

Vertical force, $F_y=4.9\times 10^{-16}\ N$

Vertical acceleration, $a_y=\dfrac{F_y}{m}$

$a_y=\dfrac{4.9\times 10^{-16}\ N}{9.11\times 10^{-31}\ kg}$

$a_y=5.37\times 10^{14}\ m/s^2$ ..........(1)

Let t is the time taken by the electron, such that,

$t=\dfrac{x}{v_x}$

$t=\dfrac{0.024\ m}{1.9\times 10^7\ m/s}$

$t=1.26\times 10^{-9}\ s$ ...........(2)

Let $d_y$ is the vertical distance deflected during this time. It can be calculated using second equation of motion:

$d_y=ut+\dfrac{1}{2}a_yt^2$

u = 0

$d_y=\dfrac{1}{2}\times 5.37\times 10^{14}\ m/s^2\times (1.26\times 10^{-9}\ s)^2$

$d_y=0.000426\ m$

$d_y=0.426\ mm$

So, the vertical distance the electron is deflected during the time is 0.426 mm. Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency

Vikki [24]

Answer:

Explanation:

f = $\sqrt{T/(m/L)} / 2L$

T = 120 N

L = 3.00 m

(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m

(wow that's massive for a "rope")

f = $\sqrt{120/12} /(2(3))$ )

f = $\sqrt{10\\}$ /6 = 0.527 Hz

This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.

A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N

5 0

3 years ago

WHAT IS THE NET FORCE REQUIRED TO GIVE AN AUTOMBILE OF MASS 1600KG AN ACCELERATION OF 4.5M/S2?

Fed [463]

Answer:

The required net force has a magnitude of 7200 N

Explanation:

Use Newton's 2nd Law to obtain the answer:

$F_{net}= m\,*\,a\\F_{net}=1600 \,*\,4.5 \,= 7200\,\,N$

4 0

4 years ago