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Shkiper50 [21]
3 years ago
15

What scenario shows responsible behavior with regard to lab safety

Physics
1 answer:
Serga [27]3 years ago
5 0

You should ALWAYS wear lab coats and safety goggles because if anything gets in your eye that will be bad.You should always wear sneakers.If any chemical falls on your open toes then that can hurt you and effect you in a lot of ways.Some labs have this rule,you are not aloud to eat or drink in lab.Hope this helps!

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A golf club exerts an average horizontal force of 1000 n on a 0.045 -kg golf ball that is initially at rest on the tee. the club
OlgaM077 [116]
The impulse (the variation of momentum of the ball) is related to the force applied by
\Delta p = F \Delta t
where \Delta p is the variation of momentum, F is the intensity of the force and \Delta t is the time of application of the force. 
Using F=1000 N and \Delta t = 1.8 ms=1.8 \cdot 10^{-3}s, we can find the variation of momentum:
\Delta p = (1000 N)(1.8 \cdot 10^{-3} s)=1.8 kg m/s

This \Delta p can be rewritten as
\Delta p = p_f - p_i = mv_f - mv_i
where p_f and p_i are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and
\Delta p = mv_f
from which we find the final velocity of the ball:
v_f =  \frac{\Delta p }{m}= \frac{1.8 kg m/s}{0.045 kg}=  40 m/s
8 0
3 years ago
As the ambulance got closer, Marge noticed that the pitch of the siren got higher. This happened because
Neko [114]

Explanation :

As the ambulance got closer, Marge noticed that the pitch of the siren got higher. This is due to the Doppler's effect.

The siren of the ambulance has a higher pitch when it approaches Marge. When the waves move away from him, it will have a lower pitch.

As the waves come closer to us, the waves become compressed and hence the frequency of the wave increases.

5 0
3 years ago
Read 2 more answers
Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m /
castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

d is the distance covered.

t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

6 0
2 years ago
16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radi
ArbitrLikvidat [17]

The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C

<h3>What does Orbital speed depend on ?</h3>

The speed of an object travelling around a circle depends on two quantities namely;

  • Its angular velocity w
  • Its distance from the center of the circle.

Given that  an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)

The given parameters are:

  • The mass of Saturn = 5.68 x 10^26 kg
  • The orbital radius = 3.00 x 105 km
  • G = 6.67 × 10-11 N·m2/kg2

Let us first calculate the gravitational field strength on the Saturn.

g = GM/r²

Substitute all the necessary parameters and convert km to m

g = (6.67 × 10^{-11} × 5.68 × 10^{26}) ÷ (300000 × 1000)²

g = 3.79 × 10^{16} ÷ 9 × 10^{16}

g = 0.421 m/s²

The  orbital speed will be

V² = gr

V² = 0.4211 × 300000 × 1000

V² = 126333333.3

V = √126333333.3

V = 11239.8 m/s

Convert it to Km/s by dividing the answer by 1000

V = 11239.8/1000

V = 11.2 Km/s

Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s

Learn more about Orbital Speed here: brainly.com/question/22247460

#SPJ1

4 0
1 year ago
A woman pulls on a 6.00-kg crate, which in turn is connected to a 4.00-kg
djverab [1.8K]

Answer:

B. is subject to a smaller net force but same acceleration.

Explanation:

F = m*a

So because our force applied is constant from the women pulling on the rope which means the acceleration is the same on both the 4kg create and the 6kg create. The only thing that changes here is the mass of the creates, so there is more tension force between the women and the 6kg create then there is between the 4kg create and the 6kg. It takes less force to move the 4kg create therefore the tension force is less between the two creates.

7 0
3 years ago
Read 2 more answers
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